Here is the equation to solve the problem above:
f(x) = (7-x)^3
y = (7-x)^3
switch y and x
x = (7 - y)^3
third root of x = 7 - y
-y = 3rootx - 7
so:<span><span>f′(x)=3^<span>√x</span>−7</span></span>
What we want to draw is the half closed interval:
I= [-5, 4) excluding 0,
as the union of 2 different intervals say a and b.
Let a be the interval containing the smallest value.
Then the smallest value of a is -5, and the largest possible value of a is 0, not included, if we want to write a as an interval, without "gaps", or "holes".
So a=[-5, 0)
similarly, b=(0, 4).
Answer: [-5, 4)=[-5, 0)∪(0, 4)
Answer:
Ans. = 18
Step-by-step explanation:
= -1 (-1)(-3)(-6)
= 1×18
=18
D is the answer for this question:))
Answer:
2(-2)-5(-2)+12
-4-(-10)+12
6+12
18
Step-by-step explanation: