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2 years ago

Help rjeiiwjdekwkwjejekw

Mathematics

2 answers:

mash [69]2 years ago

6 0

Answer:

angle H vertically opposite angle

angle D alternate angle

angle A corresponding angle

Step-by-step explanation:

Umnica [9.8K]2 years ago

5 0

Answer:

Step-by-step explanation:

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A $329.50 gaming system goes on sale for 60% off. You have a coupon for an additional 40%

Andreyy89

Answer:

Step-by-step explanation:

no because if you multiply $329.50 by .6 you get $197.7, then with the additional 40% (.4) you end up having to pay $79.08

8 0

2 years ago

Determine the type and number of solutions of 4x^2-5x+1=0

MA_775_DIABLO [31]

4x^2-5x=-1

$\sqrt{4x^2-5x} = \sqrt{-1}$ 4x^2-5x+1=0

4x+2.24x=1

6.24x=1

x= 0.16025641025641025641025641025641

7 0

2 years ago

What is the value of x -6/7=-x/84?

AURORKA [14]

Answer:

x = 72 / 85

Step-by-step explanation:

x -6/7=-x/84

x + x/84 = 6/7

84/84x + 1/84x = (12*6) / (12*7)

85/84x = ( 72 ) / ( 84 )

85/84x = 72 / 84

Multiply left and right from the = sign by 84/85 and you do that so you get a division ON THE LEFT SIDE that equals as 1... See how it works:

84/85 * { 85/84 } * x = 84/85 * { ( 72 ) / ( 84 ) }

{ (84 * 85) / ( 85 * 84) } * x = ( 84 * 72 ) / ( 85 * 84 )

(7140) / ( 7140) * x =. ( 6048 ) / ( 7140)

x = 6048 / 7140

x = 72 / 85

6 0

2 years ago

In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.

bezimeni [28]

Given:

In the circle, $m(\overarc{VUX})=152^\circ$ and $m(\angle MUV)=77^\circ$ .

To find:

The following measures:

(a) $m\angle VUX$

(b) $m\angle UXW$

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

$m(VUX)=2\times m\angle VWX$

$152^\circ=2\times m\angle VWX$

$\dfrac{152^\circ}{2}=m\angle VWX$

$76^\circ=m\angle VWX$

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

$m\angle VUX+m\angle VWX=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle VUX+76^\circ=180^\circ$

$m\angle VUX=180^\circ-76^\circ$

$m\angle VUX=104^\circ$

Now,

$m\angle UXW+m\angle UVW=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle UXW+77^\circ =180^\circ$

$m\angle UXW=180^\circ-77^\circ$

$m\angle UXW=103^\circ$

Therefore, $m\angle VUX=104^\circ$ and $m\angle UXW=103^\circ$ .

7 0

2 years ago

The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil

satela [25.4K]

The length of pencil A is 5 cm

Solution:

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

The total length of pencils A, B and C is 29 cm

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

Pencil A is 11 cm shorter then pencil B

x = y - 11 ------- eqn 2

Pencil B is twice as long a pencil C

y = 2z

$z = \frac{y}{2}$ ------ eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

$y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16$

Substitute y = 16 in eqn 2

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

5 0

3 years ago