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Anna [14]
3 years ago
8

Consider the following method:

Computers and Technology
2 answers:
Katen [24]3 years ago
8 0

Answer:

See explaination

Explanation:

public class Main {

public static void main(String[] args) {

//execution starts from here so initializing the try block for erros

try{

Scanner keyboard = new Scanner(System.in);

System.out.print("Please enter a file name: ");

String name = keyboard.next();

//the line below throws file not found exception if the given file name is not found or unable to open

Scanner file = new Scanner(new File(name));

String line = file.nextLine();

int n = file.nextInt();

//the below print line function call throws ParameterNotAllowedException if n is zero

printLine(line, n);

}//all Exceptions potentially thrown

catch(InputMismatchException e){

System.out.println("User input type mismatch\n"+e);

}catch(FileNotFoundException e){

System.out.println("Given file name is wrong or does not match");

}catch(ParameterNotAllowedException e){

System.out.println("The n given to printLine must be more than zero");

}catch(IOException ex){

System.err.println("An IOException was caught!");

}

}

//method from above goes here.

public static void printLine(String line, int numberOfTimes) throws Exception {

if (numberOfTimes <=0)

throw new ParameterNotAllowedException("Error. invalid parameter.",numberOFTimes);

for( int i=0; i<numberOfTimes; i++)

System.out.println(line);

}

}

For the user written custom Exception ParameterNotAllowedException. We need to add an exceptional class.

Which is missing from the given info:

class ParameterNotAllowedException extends Exception

{

public ParameterNotAllowedException(String s,int n)

{

// Call constructor of parent Exception

super(s);

}

}

belka [17]3 years ago
5 0

Answer:

Check the explanation

Explanation:

public class Main {

public static void main(String[] args) {

//execution starts from here so initializing the try block for errors

try{

Scanner keyboard = new Scanner(System.in);

System.out.print("Please enter a file name: ");

String name = keyboard.next();

//the line below throws file not found exception if the given file name is not found or unable to open

Scanner file = new Scanner(new File(name));

String line = file.nextLine();

int n = file.nextInt();

//the below print line function call throws ParameterNotAllowedException if n is zero

printLine(line, n);

}//all Exceptions potentially thrown

catch(InputMismatchException e){

System.out.println("User input type mismatch\n"+e);

}catch(FileNotFoundException e){

System.out.println("Given file name is wrong or does not match");

}catch(ParameterNotAllowedException e){

System.out.println("The n given to printLine must be more than zero");

}catch(IOException ex){

System.err.println("An IOException was caught!");

}

}

//method from above goes here.

public static void printLine(String line, int numberOfTimes) throws Exception {

if (numberOfTimes <=0)

throw new ParameterNotAllowedException("Error. invalid parameter.",numberOFTimes);

for( int i=0; i<numberOfTimes; i++)

System.out.println(line);

}

}

For the user written custom Exception ParameterNotAllowedException. We need to add an exceptional class.

Which is missing from the given info:

class ParameterNotAllowedException extends Exception

{

public ParameterNotAllowedException(String s,int n)

{

// Call constructor of parent Exception

super(s);

}

}

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Name the different types of constructors that a designer can provide in a class. Provide an example with a class showing many co
Marrrta [24]
By default, if you do not implement a constructor, the compiler will use an empty constructor (no parameters and no code). The following code will create an instance of the MyObject class using the default constructor. The object will have the default vauesfor all the attributes since no parameters were given.

MyObject obj = new MyObject();

Another type of constructor is one with no parameters (no-arg constructor). It is similar to the default, except you actually create this constructor. The contents of the the constructor may include anything. To call a no-arg constructor, use the same line of code as above. The constructor can look like the one below:

public MyObject() {
System.out.println("This is a no-arg constructor");
}

Lastly there is the parameterized constructor. This type of constructor takes in parameters as inputs to assign to values in the newly created object. You call a parameterized constructor as follows:

MyObject obj = new MyObject("Bob", 20);

The constructor will look like this:

public MyObject(String name, int age) {
this.name = name;
this.age = age;
}

In the constructor, the keyword "this" refers to the object, so this.name is a private global variable that is being set equal to the inputted value for name, in this case "Bob".

Hope this helps!
8 0
3 years ago
What is the space complexity of the algorithm?ArithmeticSeries(list, listSize) { i = 0 arithmeticSum = 0 while (i &lt; listSize)
blondinia [14]

Answer:

O(n) which is a linear space complexity

Explanation:

Space complexity is the amount of memory space needed for a program code to be executed and return results. Space complexity depends on the input space and the auxiliary space used by the algorithm.

The list or array is an integer array of 'n' items, with the memory size 4*n, which is the memory size of an integer multiplied by the number of items in the list. The listSize,  i, and arithmeticSum are all integers, the memory space is 4(3) = 12. The return statement passes the content of the arithmetic variable to another variable of space 4.

The total space complexity of the algorithm is "4n + 16" which is a linear space complexity.

7 0
3 years ago
Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value is consi
Darya [45]

// Variable to keep track of array size

int length = 0;

// Array itself

int array[] = {};

// while loop will take input in the array until a negative number is entered

while(input>=0){

stdin = new Scanner(System.in);

array[length] = stdin;

length +=1;

}

// int variable to terminate while loop

int i =0;

// keep track of index of output array

int y =0;

while(arr[i] != length){

// making output array

int output[]={}; bool flag;

// put the element in out put array considering if it the desired one

output[y] = array [i];

// Now check if it was the desired?

for(int z=1;z<=length;z++){

if(array[i+z]!=output[y]){

 flag = true;

}

else

{

 output[y]=0;

 y+=1;

}

if(array[i+z+1]=output[y] && flag == true){

output[y] = array[i];

y+=1;

}

}

//output the array

for(int o=0;o<y;o++)

System.out.println(output[o];

3 0
3 years ago
If you’d like to have multiple italicized words in your document, how would you change the font of each of these words
Alex787 [66]

Answer:

Use styles and modify the font of the default style

Explanation:

4 0
3 years ago
Which code results in a ValueError?<br><br> int('seven')<br> float(2.5)<br> int(7)<br> 8 / 0
SOVA2 [1]

Answer:

Int(‘seven’)

Explanation:

Took one edg

6 0
3 years ago
Read 2 more answers
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