Answer:
1
Step-by-step explanation:
because the triangles are isosceles, that means that the area of Z is 5x5x1/2, which equals 12.5
the area of X is 4.5
the area of y is 8
(8+4.5)/(12.5) = 1
Answer:
a. The percentage of vehicles who pass through this construction zone who are exceeding the posted speed limit =90.82%
b. Percentage of vehicles travel through this construction zone with speeds between 50 mph and 55 mph= 2.28%
Step-by-step explanation:
We have to find
a) P(X>40)= 1- P(x=40)
Using the z statistic
Here
x= 40 mph
u= 44mph
σ= 3 mph
z=(40-44)/3=-1.33
From the z-table -1.67 = 0.9082
a) P(X>40)=
Probability exceeding the speed limit = 0.9082 = 90.82%
b) P(50<X<55)
Now
z1 = (50-44)/3 = 2
z2 = (55-44)/3= 3.67
Area for z>3.59 is almost equal to 1
From the z- table we get
P(55 < X < 60) = P((50-44)/3 < z < (55-44)/3)
= P(2 < z < 3.67)
= P(z<3.67) - P(z<2)
= 1 - 0.9772
= 0.0228
or 2.28%
Answer:
<h2>(+)(-)√30</h2><h2>#option c</h2>
Step-by-step explanation:
<u>☆</u><u> </u><u>REFER</u><u> TO</u><u> THE</u><u> </u><u>ATTACHMENT!</u>
<h3>
<u>♰</u><u>H</u><u>ope </u><u>it </u><u>helps</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u></h3>
The
<u>correct answer</u> is:
$5,000.
Explanation:
When it is first purchased, the depreciation expense is calculated using the formula:
The cost was $23,000; the salvage value was $3,000; and the useful life was 8 years:
This means the value of the vehicle depreciates $2500 per year.
After 4 years, the vehicle would depreciate 2500(4) = $10,000.
This makes the new value $23000-$10000 = $13000.
Reevaluating the depreciation expense at this point, we use $13000 for the "cost" (current value), $3000 is still the salvage value, and now the total useful life was 6; we take 4 off of this, since it has already been 4 years:
The depreciation expense in year 5 is $5,000.
Answer:
uh .. hold on let me come back to this