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2 years ago

Find x and then any unknown angles in the quadrilateral

Mathematics

1 answer:

sweet [91]2 years ago

7 0

Answer:

klll99

=Step-by-step explanation:

=00997.9987

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Trina is making a friendship necklace at summer camp using 1.6 cm beads. What is a reasonable estimate for the length if she use

diamong [38]

C would be your answer

5 0

3 years ago

If Colorado Springs, Colorado, has 1.6 times more days of sunshine than Boston, Massachusetts, how many days of sunshine does ea

Kay [80]

C = 1.6b
c + b = 442

1.6b + b = 442
2.6b = 442
b = 442 / 2.6
b = 170 <== Boston

c = 1.6b
c = 1.6(170)
c = 272 <== Colorado Springs

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3 years ago

Cytosine always pairs with

sleet_krkn [62]

Answer: guanine

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the length of the following curve. If you have a grapher, you may want to graph the curve to see what it looks like.

stepladder [879]

The length of the curve $y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

$y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6

Start by differentiating the curve function

$y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x$

Evaluate

$y' = x(9x^2 + 6)^\frac 12$

The length of the curve is calculated using:

$L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx$

This gives

$L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx$

Expand

$L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx$

This gives

$L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx$

Express as a perfect square

$L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx$

Evaluate the exponent

$L =\int\limits^6_3 {3x^2 + 1} \ dx$

Differentiate

$L = x^3 + x|\limits^6_3$

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units