You have to put the number under 1 so you would get 1 over -27
Answer:
±0.06
Step-by-step explanation:
The range is 0.28 - 0.16 = 0.12. So half of that is 0.06.
Find the volume of the first figure, then find the volume of the second figure, then add them together.
V=lwh
V(1)=(15)(12)(6)
= 1,080in^3
V(2)=(12)(6)(6)
= 432in^3
--------------------------------------------
1,080+432= 1,512 in^3
--------------------------------------------
Your answer should be 1,512
Since you're looking for the chance that the defective player occurs twice, you need to find the chance your friend receives a defective player given that you also receive one. The chance you receive a defective player is 4%, or 0.04. If you friend also receives a defective player, then the chance of both occurring is 4% of 4%, or 0.04 * 0.04, which equals 0.0016. So the probability that you can a friend both receive a defective player is 0.16%.
