Answers: b, d and e
b.The graph has a relative minimum
d. The graph has an x intercept at 3,0
e. the graph has an y intercept at 0,-15
f(x)=(x+5)(x-3)
The given equation is in the form of f(x) = a(x-b)(x-c)
If 'a' is positive then graph has a relative minimum
If 'a' is negative then graph has a relative maximum
Here a=1 that is positive so graph has a relative minimum .
To find x intercept we set f(x) =0 and solve for x
0=(x+5)(x-3)
x+5 =0 -> x = -5 so x intercept is (-5,0)
x - 3=0 -> x= 3 so x intercept is (3,0)
To find y intercept we plug in 0 for x
y=(x+5)(x-3)
y=(0+5)(0-3) = -15
so y intercept is (0,-15)
Your answer is $29.13 I hope this helped, I apologize for the late response!
Answer:
x= 0 , 
, 
Step-by-step explanation:
Given, equation is ![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D)
+ ![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D)
= ![4\sqrt[3]{x}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7Bx%7D)
. →→→ (1)
Now, by cubing the equation on both sides, we get
( + )³ = ()³
⇒ (15x-1) + (13x+1) + 3×× ( + ) = 64 x.
⇒ 28x + 3×× () = 64x.
(since from (1), + = )
⇒ 12× × (![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D)
)= 36x.
⇒ 3x = ![\sqrt[3]{(15x-1)(13+1)(x)}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%2815x-1%29%2813%2B1%29%28x%29%7D)
.
Now, once again cubing on both sides, we get
(3x)³ = ()³.
⇒ 27x³ = (15x-1)(13x+1)(x).
⇒ 27x³ = 195x³ + 2x² - x
⇒ 168x³ + 2x² - x = 0
⇒ x(168x² + 2x -1) = 0
⇒ by, solving the equation we get ,
x = 0 ; x = ; x =
therefore, solution is x= 0 , ,
Answer:
z = - 20
Step-by-step explanation:
3 - z/4 = 8
-z/4 = 5
z = -20
