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3 years ago

Which expression is equivalent to16x2+81?

1 answer:

4 0

16*X² +81

The answer is 3

(4x+9i)(4x−9i) = (4x+9i)*4x -9i((4x+9i)) = 16x2 +36i -36i -81i2 = 16x² -81(-1)

= 16x² +81

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Which expression and value represents 9 less than the quotient of 18 and 3?

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Answer:

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3 years ago

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Nichole's rotating sprinkler waters her lawn up to a radius of 7 feet. What is the maximum number of square feet of lawn Nichole

Marysya12 [62]

Answer:

153.9 ft²

Step-by-step explanation:

Given that:

Radius of circular lawn = 7 feets

To obtain the maximum number of square feet of lawn Nichole can expect the sprinkler to cover ; find the area of the lawn

Area of a circle, A = πr²

A = π * 7 * 7

A = 153.93804

A = 153.9 ft²

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2 years ago

olga nikolaevna [1]

Answer:5

Step-by-step explanation:>

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o f(x) = 2( 3 )

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(1.1

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2 years ago

Line r and m are parallel. Find the value of x.

Evgesh-ka [11]

Answer:

Answer:

10x-3=7x+45 corresponding angle

10x-7x=45+3

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value of x is 16.

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3 years ago

two leaky containers are filling with water. water enters container a at a rate of 2/3 cup per 1/2 minute and leaks out at a rat

kipiarov [429]

container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .

<u>Step-by-step explanation:</u>

Here we have , two leaky containers are filling with water. water enters container a at a rate of 2/3 cup per 1/2 minute and leaks out at a rate of 1/4 cup per 3/4 minute. water enters container b at a rate of 3/4 cup per 1/2 minute and leaks out at a rate of 1/2 cup per 3/4 minute. We need to find which container needs to be filled faster in order for both containers to gain the same amount of water per minute . Let's find out:

Rate of Filling container A:

⇒ $\frac{\frac{2}{3} }{\frac{1}{2} }$

⇒ $\frac{2}{3} (2) = \frac{4}{3}$

Rate of leaking Container A:

⇒ $\frac{\frac{1}{4} }{\frac{3}{4} }$

⇒ $\frac{1}{4} (\frac{4}{3}) = \frac{1}{3}$

Amount of water in Container A in one minute :

⇒ $\frac{4}{3} - \frac{1}{3} = 1$

No , following same for Container B

Rate of Filling container B:

⇒ $\frac{\frac{3}{4} }{\frac{1}{2} }$

⇒ $\frac{3}{4} (\frac{2}{1}) = \frac{3}{2}$

Rate of leaking Container B:

⇒ $\frac{\frac{1}{2} }{\frac{3}{4} }$

⇒ $\frac{1}{2} (\frac{4}{3}) = \frac{2}{3}$

Amount of water in Container B in one minute :

⇒ $\frac{3}{2} - \frac{2}{3} = \frac{5}{6}$

Since , Rate of water per minute in container A is 1 and , Rate of water per minute in container B is 5/6 , container A fills faster by container B by

⇒ $1-\frac{5}{6} = \frac{1}{6}$

Therefore , container B needs to be filled faster in order for both containers to gain the same amount of water per minute , and by 1/6 water per minute .

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3 years ago