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geniusboy [140]
3 years ago
7

Which expression is equivalent to16x2+81?

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0
16*X² +81

The answer is 3

(4x+9i)(4x−9i) = (4x+9i)*4x -9i((4x+9i)) = 16x2 +36i -36i -81i2 = 16x² -81(-1)

= 16x² +81
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I am greater than 15 I am less than 21 I have 8 ones
PSYCHO15rus [73]

Answer:

18

Step-by-step explanation:

bc 8 digits in the ones place, and less than 21 greater than 15

7 0
3 years ago
Read 2 more answers
PLZ HURRY ITS TIMEDDDDD
GaryK [48]

A. 1/5k - 2/3j and -2/3j + 1/5k

Step-by-step explanation:

Equivalent expressions are expressions that are the same even though they may appear different.When you plug in a value to represent a variable in these expression, they will give same answer when simplified.

In

1/5k - 2/3j and -2/3j + 1/5k you notice the operation signs in the terms has been maintained though the position of the terms shifted.

Learn More

Equivalent expressions :brainly.com/question/280220

Keywords: expressions, equivalent

#LearnwithBrainly

8 0
3 years ago
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How do you solve <br> 8|x+2|-6=5|x+2|+3
sergejj [24]

Answer:

x = 1 or x = -5

Step-by-step explanation:

Solve for x over the integers:

8 abs(x + 2) - 6 = 5 abs(x + 2) + 3

Subtract 5 abs(x + 2) - 6 from both sides:

3 abs(x + 2) = 9

Divide both sides by 3:

abs(x + 2) = 3

Split the equation into two possible cases:

x + 2 = 3 or x + 2 = -3

Subtract 2 from both sides:

x = 1 or x + 2 = -3

Subtract 2 from both sides:

Answer:  x = 1 or x = -5

7 0
3 years ago
A triangle with two congruent sides is always a 45-45-90 triangle.<br><br> A. True<br><br> B. False
MissTica
B. False 

Not necceserly 

It can be 10 10 and 160
Since it has to sum up to 180
6 0
3 years ago
Read 2 more answers
Can someone plz help me with Algebra 2....... :) Will give Brainliest!!
Anarel [89]
Using logarithms property of log(x)+log(y)=log(xy)
so here, you can sum the equation to;
log((x+6)*(x-6))=2
so you can simply say that;
log_{8}((x+6)( x-6))=2
and by multiplying (x+6)*(x-6)
log_{8}(x^2-36)=2
and as you know also that;
a^{b}=c is same as log _{a}c=b
so you can simply state it as;
8^2=x^2-36&#10;64=x^2-36&#10;64+36=x^2&#10;x^2=100&#10;x=10
And you can check your work by substituting with 10 instead of x in the original function.
Hope this helps!
6 0
3 years ago
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