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dusya [7]
3 years ago
7

Which of the following best describes (x + 6)(x – 6)

Mathematics
2 answers:
FromTheMoon [43]3 years ago
5 0

1) take x*x

2) x*-6

3)6*x

4)6*-6

answer x^2-36

STatiana [176]3 years ago
5 0

Answer:The product of a binomial and a trinomial

Step-by-step explanation:

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Hi doe s anyone know the answer
Svetlanka [38]

Answer:

<u>Regular Polygon:</u>

<em>C, E  </em>(All sides and angles are equal)

<u>Irregular Polygon:</u>

<em>A, B, </em>(Not all sides or angles are equal)

<u>Not a Polygon</u>

<em>E, F </em>(There are curves and not a closed shape)

Hope this helps! Comment if you have any questions :)

<em />

5 0
3 years ago
Read 2 more answers
All 4 questions please
scZoUnD [109]

Answer:

  1. π = S/2πrh
  2. v = √2E/m
  3. b = (-7a+c)/2
  4. x =3y-1

Step-by-step explanation:

1.

S = 2\pi rh\\Divide\:both\sides\:of\:the\:equation\:by\:2rh\\\\\frac{S}{2rh} = \frac{2 \pi rh}{2 rh} \\\\\pi = \frac{S}{2rh}

2.

E = \frac{1}{2} mv^2\\\\E = \frac{mv^2}{2} \\\\Cross\:multiply\\\\2E =mv^2\\Divide\:both\:sides\:of\:the\:equation\:by\:m\\\frac{2E}{m} = \frac{mv^2}{m} \\\\\frac{2E}{m} =v^2\\Square\:root\:both\:sides\:of\:the\:equation\\\sqrt{\frac{2E}{m} } = \sqrt{v^2} \\\\\sqrt{\frac{2E}{m} } =v\\\\v =\sqrt{\frac{2E}{m} }

3.

7a+2b =c\\Isolate\:b\\\\2b =c-7a\\2b= -7a+c\\Divide\:both\:sides\:of\:the\:equation\:by \:2\\\frac{2b}{2} =\frac{-7a+c}{2} \\\\b = \frac{-7a+c}{2}

4.

y = \frac{1}{3} (x+1)\\\\y = \frac{x+1}{3}\\\\Cross\:multiply \\3y =x+1\\Isolate \:x\\3y -1=x\\\\x =3y-1

7 0
3 years ago
Solve 3x+2y=4 4x+3y=7 algebraically
Leona [35]
Step 1. Multiply first equation with -3 and the second one with 2. You'll get:
\left \{ {{-9x-6y=-12} \atop {8x+6y=14}} \right.

Step 2. Add both equations together. You'll get:
-x=2, which gives x = -2

Step 3. Replace x = -2 in the first equation and calculate y.
3(-2)+2y=4\\&#10;y=\frac{4+6}{2}=5

The solution is: x=-2, y=5
8 0
3 years ago
What is the correct classification of the system of equations below? 14x + 2y = 10 y + 7x = -5 parallel coincident intersecting
marissa [1.9K]
In standard form the two equations are
  7x +y = 5
  7x +y = -5

The equations describe lines that are parallel.
5 0
3 years ago
Here is a triangular pyramid and its net.
bazaltina [42]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

3 0
3 years ago
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