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mamaluj [8]
3 years ago
8

What two values can replace -17x?

Mathematics
1 answer:
drek231 [11]3 years ago
6 0
The answer is 6 or 8 which ever one u feel comfortable with
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Solve for X<br> A) 13<br> B) 5<br> C) 14<br> D) 1
Drupady [299]

Answer:

B) 5

Circle is 360 degr. So (21x+9) +(23x-5) +(26x+6)=360

Combine like terms 70x+10=360

Additive inverse -10 from both sides, 70x= 350

Divide both side by 70 division Property of Equality x=5.

Check your answer by substituting 5 back into original solution!

Step-by-step explanation:

3 0
2 years ago
An equation with an exponent is called an exponential equation. True False
lyudmila [28]

Answer:

true

Step-by-step explanation:

7 0
3 years ago
Pls plz plz i need the answers help me
EastWind [94]

Answer:

24 units squared

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Trent's salary used to be $143,020. After changing the amount of time he works, he has begun earning $78,661. By what percent di
svlad2 [7]

Answer:

The salary decreased by 45%

Step-by-step explanation:

Given,

The previous salary of Trent is $143,020

The current salary of Trent is $78,661

The decrease in salary is ($143,020 - $78,661) = $64,359

When he used to get $143,020, the decrease in salary is = $64,359

When he used to get $1, the decrease in salary is = $64,359/$143,020

When he used to get $100, the decrease in salary is = $(64,359/143,020)*100

                                                                                        = 45%

Therefore, there is a decrease in salary by 45%.

6 0
3 years ago
What are the real zeros of the function g(x) = x^3 + 2x^2 − x − 2?
PSYCHO15rus [73]
If there are real roots to be found for this polynomial, the Rational Root Theorem and synthetic division are the best way to find them. I teach from a book that uses c and d for the possible roots of the polynomial.  C is our constant, 2, and d is the leading coefficient, 1.  The factors of 2 are +/- 1 and +/-2.  The factors for 1 are +/-1 only.  Meaning, in all, there are 4 possibilities as roots for this polynomial.  But there are only 3 total (because our polynomial is a third degree), so we have to find the first one, at least, from our possibilities above.  Let's try x = -1, factor form (x + 1).  If there is no remainder when we do the synthetic division, then -1 is a root.  Put -1 outside the "box" and the coefficients from the polynomial inside: -1  (1  2  -1  -2).  Bring down the first coefficient of 1 and multiply it by the -1 outside to get -1.  Put that -1 up under the 2 and add to get 1.  Multiply 1 times the -1 to get -1 and put that -1 up under the -1 and add to get -2.  -1 times -2 is 2, and -2 + 2 = 0.  So we have our first root of (x+1).  The numbers we get when we do the addition along the way are the coefficients of our new polynomial, the depressed polynomial (NOT a sad one cuz it hates math, but a new polynomial that is one degree less than that of which we started!).  The new polynomial is x^{2} +x-2=0.  That can also be factored to find the remaining 2 roots.  Use standard factoring to find that the other 2 solutions are (x+2) and (x-1).  Our solutions then are x = -2, -1, 1, choice B from above.
6 0
3 years ago
Read 2 more answers
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