Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Answer:
4
Step-by-step explanation:
y=8x+4
y=mx+b where m=slope and b=y-intercept
b=4
Answer: x^2 + 40x
Nothing can further be done with the topic.....
I think you forgot to add the cord picture?
Solution:
<u>Note that:</u>
- 2(Perimeter of smaller triangle) = Perimeter of larger triangle
<u>Using the perimeter of the smaller triangle, solve for x.</u>
- 2(Perimeter of smaller triangle) = Perimeter of larger triangle
- => 2(3.5 + x + h) = 7 + 4 + 2h
- => 7 + 2x + 2h = 7 + 4 + 2h
- => 2x = 4
- => x = 2
The length of x is 2 units.
