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tatyana61 [14]
3 years ago
15

What is true about any point on a coordinate plane with a negative x-coordinate and a y-coordinate that is not zero?

Mathematics
1 answer:
Ivenika [448]3 years ago
8 0
It will always be on the first or third quartile of the graph, or the point will always be on the “left side” of the graph. Brainliest answer?;)
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3 years ago
Simplify (4^7/5^2)^3
Nuetrik [128]

Answer:

4²¹/5⁶ or 4398046511104/15625

Step-by-step explanation:

Remember, when raising a term with an exponent to some power, you must multiply the powers.

(\frac{4^{7} }{5^{2} })^{3} \\\\ = (\frac{(4^{7})^{3} }{(5^{2})^{3} }) \\\\= \frac{4^{7 * 3} }{5^{2* 3} } \\\\= \frac{4^{21} }{5^{6} } \\\\=\frac{4398046511104}{15625}

5 0
3 years ago
Read 2 more answers
Can anyone help me please?
Nadya [2.5K]

Answer:

s ≤ -18

Step-by-step explanation:

Multiply both sides of the inequality by -3. Since the multiplier is negative, you need to reverse the comparison symbol.

(-3)(-s/3) ≤ (-3)(6)

s ≤ -18

_____

If you multiply by a positive number, you don't need to reverse the symbol. Hence multiplying by 3 gives ...

-s ≥ 18

You can now add s to both sides:

0 ≥ 18 + s

and subtract 18 from both sides:

-18 ≥ s

Of course, this is the same relationship as ...

s ≤ -18

6 0
4 years ago
Solve the equation and enter the value of x below.<br> -4x-13 = 51<br> X=<br> Answer here
ololo11 [35]

Answer:

x = -16

Step-by-step explanation:

-4x - 13 = 51

-4x = 51 + 13

-4x = 64

x = -16

3 0
3 years ago
If n2 = 1/16, then n could be which of the following?<br> -8<br> -1/4<br> 1/4
andreyandreev [35.5K]

n^2=\dfrac{1}{16}\\\\n=-\dfrac{1}{4} \vee n=\dfrac{1}{4}

6 0
3 years ago
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