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3 years ago

5

Tina wrote the equations 3x-y=9 and 4x+y=5. What can Tina conclude about the solution to this system of equations?

2 answers:

sergiy2304 [10]3 years ago

5 0

The answer to your question is: C. 2,-3
Hope this helps

TiliK225 [7]3 years ago

4 0

ANSWER IS C
3x-y=9 eq 1
4x+y=5 eq2
y=5-4x eq3 from eq 2
substitute value of y in equation 1
3x-5+4x=9
x=2
put value of x in eq number 3
y= 5-4(2)
y=5-8
y=-3
SO ANSWER IS C THAT IS 2,-3
x=2 y= -3

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3 years ago

student expanded an expression, as shown. Is the student's work correct? Explain why or why not. −6 ( 4x − 2 13 ) −6(4x) + 6 ( −

sleet_krkn [62]

Answer:

No, the student's work is not correct.

Step-by-step explanation:

Given : Student expanded an expression, as shown.

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$-6(4x)+6(-\frac{2}{13} )$

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To find : Is the student's work correct?

Solution :

The expansion of student is not correct.

Follow the below steps to get correct solution and student mistake,

Step 1 - Write the expression,

$-6(4x-\frac{2}{13} )$

Step 2 - Apply distributive property, $a(b+c)=ab+ac$

$=(-6)(4x)+(-6)(-\frac{2}{13})$

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3 years ago

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Answer:

(1 $\frac{1}{3}$ , 2 $\frac{1}{3}$ )

Step-by-step explanation:

Given the 2 equations

7x - y = 7 → (1)

x + 2y = 6 → (2)

Multiplying (1) by 2 and adding to (2) will eliminate the y- term

14x - 2y = 14 → (3)

Add (2) and (3) term by term to eliminate y

15x = 20 ( divide both sides by 15 )

x = $\frac{20}{15}$ = $\frac{4}{3}$ = 1 $\frac{1}{3}$

Substitute this value of x into either of the 2 equations and solve for y

Substituting in (2)

$\frac{4}{3}$ + 2y = 6

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