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3 years ago

12 is 80% of what number?

Mathematics

2 answers:

anzhelika [568]3 years ago

8 0

15

Mark me brainliest! Hope it helps!!! :)

Nata [24]3 years ago

5 0

Answer:

Step-by-step explanation:

x • 4/5 = 12

Multiply both sides by 5/4 to cancel out the 4/5

12 • 5/4 = 60/4

60/4 = 15

x = 15

Plug in 15 for x to make sure it works.

15 • 4/5 = 60/5

60/5 = 12✓

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How much longer is the distance from the library to the park to the train station than the distance from the library straight to

Slav-nsk [51]

Answer:

2.14

Step-by-step explanation:

2.14+3.82= 5.96

5.96-3.82= 2.14

So, your answer would be 2.14

7 0

3 years ago

4 2/3 divided by 1/2

ycow [4]

Answer:

9 1/3

Step-by-step explanation:

1. Make 4 2/3 into a improper fraction

4 2/3= 14/3

2. Keep, change, flip

14/3 x 2/1

3. Multiply

14/3 x 2/1= 28/3

4. Simplify

28/3= 9 1/3

(btw keep, change, flip basically means to keep the first fraction the way it is, change the division sign to a multiplication sign, then flip the second fraction so the original denominator is the new numerator, and vise versa.)

3 0

3 years ago

Read 2 more answers

2. Mrs. Long just got a new puppy! The puppy is learning how to run on hard wood floors. The puppy is running at a rate if 4 fee

jolli1 [7]

1.The puppy will run into the wall after 5 seconds

8 0

4 years ago

Read 2 more answers

A 3ft child casts a 2ft shadow at the same time a tree casts a shadow that is 6ft long how tall is the tree?

Anettt [7]

Answer:

$h_t=9ft$

Step-by-step explanation:

From the question we are told that:

Height of child $h_c=3ft$

Height of child's shadow $h_c_s=2ft$

Height of tree's shadow $h_t_s=6ft$

Since position of Sun remains constant

Generally the equation for Height of tree h_t mathematically given by

$h_t=f_{ts}\frac{h_c}{h_c_s}$

$h_t=6*\frac{3}{2}$

$h_t=9ft$

4 0

3 years ago

Select the correct answer from each drop-down menu. The base of pyramid A is a rectangle with a length of 10 meters and a width

ASHA 777 [7]

Step-by-step explanation:

The formula of a volume of a pyramid:

$V=\dfrac{1}{3}BH$

B - base area

H - height

H - height of pyramids

Pyramid A:

$B=(10)(2)=200\ m^2$

$V_A=\dfrac{1}{3}(200)H=\dfrac{200}{3}H\ m^3$

Pyramid B:

$B=10^2=100\ m^2$

$V_B=\dfraC{1}{3}(100)H=\dfrac{100}{3}H\ m^3$

$V_A>V_B\\\\V_A=2V_B$

The volume of the pyramid A is twice as large as the volume of the pyramid B.

The new height of pyramid B: 2H

The new volume:

$V_{B'}=\dfrac{1}{3}(100)(2H)=\dfrac{200}{3}H\ m^3$

The volume of the pyramid A is equal to the volume of the pyramid B.

3 0

3 years ago