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Alex777 [14]
3 years ago
15

The law of cosines is a2+b2-2abcosC=c2 find the value of 2abcosC

Mathematics
2 answers:
quester [9]3 years ago
7 0
Isolating 2abCos(c) on one side of the equation and using the given values of a, b and c we can find the answer to this question as shown below:

a^{2} + b^{2} -2ab*cos(C)=c^{2}  \\  \\ 
2ab *cos(C)=  a^{2} + b^{2} - c^{2}  \\  \\ 
2ab *cos(C)=2^{2} + 2^{2}- 1^{2} \\  \\ 
2ab*cos(C) = 7
Westkost [7]3 years ago
4 0
2ab * cos (C)= 7

hope this helps you
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