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3 years ago

The law of cosines is a2+b2-2abcosC=c2 find the value of 2abcosC

2 answers:

7 0

Isolating 2abCos(c) on one side of the equation and using the given values of a, b and c we can find the answer to this question as shown below:

$a^{2} + b^{2} -2ab*cos(C)=c^{2} \\ \\ 
2ab *cos(C)= a^{2} + b^{2} - c^{2} \\ \\ 
2ab *cos(C)=2^{2} + 2^{2}- 1^{2} \\ \\ 
2ab*cos(C) = 7$

Westkost [7]3 years ago

4 0

2ab * cos (C)= 7

hope this helps you

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2 years ago

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Step-by-step explanation:

Given:

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3 years ago

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You should multiply the expression by $\frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}$ in order to rationalize the denominator

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Answer: Step-by-step explanation:

Step-by-step explanation:

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