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Paladinen [302]
4 years ago
7

Find the distance between C(-4,- 8) and D(2, 2)

Mathematics
1 answer:
White raven [17]4 years ago
3 0

Answer & Step-by-step explanation:

First, we must know the distance formula.

Distance(d)=\sqrt{(x2-x1)^2+(y2-y1)^2}

Know, we plug in our numbers for x1, y1, x2, and y2.

d=\sqrt{(2-(-8))^2+(2-(-4))^2}

d=\sqrt{(10)^2+(6)^2}

d=\sqrt{100+36}

d=\sqrt{136}

d=11.7

So, the distance between C and D is 11.7 units.

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2.6y-4/15y+7/6y=7/3y
ohaa [14]

Answer:

y=0

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2.6y-4/15y+7/6y=7/3y

2.6y-(-)4/15y+7/6y=7/3y

(2.6y-4/15y+7/6y)=7/3y (combine like terms)

7/2y = 7/3y

Step 2: Subtract 7/3y from both sides.

7/2y - 7/3y =  7/3y - 7/3y

7/6y = 0

Step 3: Multiply both sides by 6/7

6/7 . 7/6y = 6/7 . 0

y = 0

3 0
3 years ago
If m is the midpoint of segment JK, JM equals 7x minus 32, and MK equals 89 minus 4x, what is MK?
KonstantinChe [14]

Step-by-step explanation:

Imagine this segment, given that m is the midpoint of segment JK...

      J________M________K

   JM = 7x-32        MK = 89 - 4x (given)

If m is the midpoint, then JM and MK are the same lengths (equal to each other). We can use that to first find what <em>x</em> is.

7x -32 = 89 - 4x\\

Steps to find x (we have to get x by itself):

7x - 32 + 4x = 89 - 4x  +4x

11x -32 = 89

11x -32 +32 = 89 +32

11x = 121

\frac{11x}{11} = \frac{121}{11}

x=11 (we haven't found the answer yet! we only found x)

Now that we found x, we can find segment MK. Now we know that:

MK = 89 - 4x  

x= 11

Let's plug x into the equation:

MK = 89 - 4(11)\\MK = 89- (44)\\MK = 45

Answer: MK= 45

4 0
3 years ago
Jamal needs several feet of wood for a birdhouse
Maurinko [17]

Answer:

36

Step-by-step explanation:

multiple by the length value by 3

3 0
3 years ago
Determine whether line AB and line CD are parallel, perpendicular, or neither. A( 4, 2), B(-3, 1), C(6, 0), D(-10, 8)
Lapatulllka [165]

Answer:

<h2>neither</h2>

Step-by-step explanation:

If AB an CD are parallel, then their slopes are the same.

If AB and CD are perpendicular, then the product of their slopes is equal -1.

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

Calculate the both slope:

A(4,\ 2),\ B(-3,\ 1)\\\\m_{AB}=\dfrac{1-2}{-3-4}=\dfrac{-1}{-7}=\dfrac{1}{7}\\\\C(6,\ 0),\ D(-10,\ 8)\\\\m_{CD}=\dfrac{8-0}{-10-6}=\dfrac{8}{-16}=-\dfrac{1}{2}\\\\=============================

m_{AB}\neq m_{CD}

The line AB and line CD are not parallel

m_{AB}\cdot m_{CD}=\left(\dfrac{1}{7}\right)\left(-\dfrac{1}{2}\right)=-\dfrac{1}{14}\neq-1

The line AB and line CD are not perpendicular.

6 0
3 years ago
Write the algebraic expression that matches each graph.
goldfiish [28.3K]

Answer:

f(x) = |x - 2| - 2

Step-by-step explanation:

Based on the shape of the graph, it's an absolute value function.

so the template for it is f(x) = |x|

From there, you can make some additions to show how much the graph has shifted from the template equation

since the graph went over to the left by 2 units and down by 2 units, this is added into the equation as follows:

f(x) = |x - 2| - 2

4 0
2 years ago
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