The discriminant of this equation is 49. The solutions for this equation are x=2 and x=-
I hope that helps.
Answer:
A
Step-by-step explanation:
When you read the question it says that her average speed from the library to the gym is 15 mph less than her speed from her home to the library. So x - 15 is what describes that situation.
If it is A it cannot be anything else.
B is incorrect. x - 15 is not a time. It is a rate. It can be used to develop the amount of time, but by itself it is still A.
C is incorrect. Her average speed from her house to the library is x
D is incorrect. The distance is given as the same as from her home to the library as from the library to the gym. Both are 4
Answer:
$11.50. Each CD cost $11.50.
Step-by-step explanation:
When trying to determine how much each CD cost, we need to know our total cost, $57.50, and how many CDs were bought, 5.
Since 5 CDs cost $57.50, we can divide our total cost by the number of CDs purchased to find the cost of each CD. 57.50 / 5 = 11.50
Answer:
7,11
Step-by-step explanation:
The width is x. x+4= the length. The area is side times side, so it’s
x × (x+4) = 77
We can simplify this to:
x × x + x × 4 = 77
x^2 + 4x = 77
x^2 + 4x - 77 = 0 This is a quadratic equation. So we can solve using the quadratic formula:
x = 
->
That’s the positive solution and that’s x, the width. So the width is 7 and the length is 7+4=11
A) an equilateral triangle
A) an equilateral triangleA) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangleA) an equilateral triangle
A) an equilateral triangleA) an equilateral triangle
A) an equilateral triangleA) an equilateral triangleA) an equilateral triangle
A) an equilateral triangleA) an equilateral triangle
A) an equilateral triangleA) an equilateral triangle
A) an equilateral triangle
A) an equilateral triangleA) an equilateral triangle
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