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IrinaK [193]
3 years ago
7

The mean of a soccer team goals is 6 goals after 4 games. If the team scored 5 goals in the first game, 6 goals in the second ga

me and 6 goals in the third game, how many goals did they score at the 4th game?
Mathematics
2 answers:
Sedaia [141]3 years ago
8 0
7


Mark brainliest please


Hope this helps you
Hitman42 [59]3 years ago
8 0
<h3>Answer:  7 goals</h3>

=====================================================

Work Shown:

We have this set of data

\begin{tabular}{|l|l|}\textbf{game} & \textbf{goals}\\        1 & 5 \\        2 & 6 \\        3 & 6\\         4 & x    \end{tabular}

where x is some positive whole number. Add up everything in the second column:

5+6+6+x = x+17

This represents the total number of goals made over the four games.

Divide this over the number of games played (4) and set that equal to the mean of 6. Solve for x.

(x+17)/4 = 6

x+17 = 4*6

x+17 = 24

x = 24-17

x = 7

7 goals were scored in the fourth game.

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A survey is made to determine the number of households having electric appliances in a certain city. It is found that 75% have r
Mashcka [7]

Answer:

The probability that a household has at least one of these appliances is 0.95

Step-by-step explanation:

Percentage of households having radios P(R) = 75% = 0.75

Percentage of households having electric irons P(I) = 65% = 0.65

Percentage of households having electric toasters P(T) = 55% = 0.55

Percentage of household having iron and radio P(I∩R) = 50% = 0.5

Percentage of household having radios and toasters P(R∩T) = 40% = 0.40

Percentage of household having iron and toasters P(I∩T) = 30% = 0.30

Percentage of household having all three P(I∩R∩T) = 20% = 0.20

Probability of households having at least one of the appliance can be calculated using the rule:

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The probability that a household has at least one of these appliances is 0.95

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