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Levart [38]
3 years ago
7

What is 1,995,298 rounded to the nearest 10,000

Mathematics
2 answers:
hoa [83]3 years ago
6 0
Salutations!

What is 1,995,298 rounded to the nearest 10,000?

To round the number to the nearest 10,000, you need to know whether the number next 10,000 place is greater than 5 or lesser than 5. If its greater, you need to round up. If its lesser than 5, you need to round down.

1,995, 298 ≈ 2,000,000.

Hope I helped (:

Have a great day!
iren [92.7K]3 years ago
4 0
the answer is 2,000,000
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alexdok [17]

Answer:

2i and -2i

Step-by-step explanation:

I'll change u to x to be easier to understand.

x^2 = -4

sqrt(x^2) = sqrt(-4)

sqrt(-4) = 2i, or -2i

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V125BC [204]

Answer:

Option C (f(x) = -x^2 + 2x + 4)

Step-by-step explanation:

In this question, the first step is to write the general form of the quadratic equation, which is f(x) = ax^2 + bx + c, where a, b, and c are the arbitrary constants. There are certain characteristics of the values of a, b, and c which determine the nature of the function. If a is a positive coefficient (i.e. if a>0), then the quadratic function is a minimizing function. On the other hand, a is negative (i.e. if a<0), then the quadratic function is a maximizing function. Since the latter condition is required, therefore, the first option (f(x) = 4x^2 + 6x - 1) and the last option (f(x) = x^2 + 4x - 4) are incorrect. The features of the values of b are irrelevant in this question, so that will not be discussed here. The value of c is actually the y-intercept of the quadratic equation. Since the y-intercept is 4, the correct choice for this question will be Option C (f(x) = -x^2 + 2x + 4). In short, Option C fulfills both the criteria of the function which has a maximum and a y-intercept of 4!!!

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One way to find p is to notice that the part on the left hand side within the parentheses can be written as a square:

\dfrac9{25a^4}=\dfrac{3^2}{5^2(a^2)^2}=\left(\dfrac3{5a^2}\right)^2

So you could write

\left(\left(\dfrac3{5a^2}\right)^2\right)^p=\left(\dfrac3{5a^2}\right)^{2p}=\dfrac3{5a^2}

Since these two expressions are equal, and the bases are the same, you know the exponents must be equal, with the exponent on the right hand side being 1. So 2p=1, or p=\dfrac12.
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oee [108]

Answer:

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Step-by-step explanation:

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