Answer:
see explanation
Step-by-step explanation:
The common difference d of an arithmetic sequence is
d =
-
=
- 
Substitute in values and solve for k, that is
5k - 1 - 2k = 6k + 2 - (5k - 1)
3k - 1 = 6k + 2 - 5k + 1
3k - 1 = k + 3 ( subtract k from both sides )
2k - 1 = 3 ( add 1 to both sides )
2k = 4 ⇒ k = 2
--------------------------------------------------------
The n th term of an arithmetic sequence is
=
+ (n - 1)d
= 2k = 2 × 2 = 4 and
d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5
Hence
= 4 + (7 × 5) = 4 + 35 = 39
Answer:
- 6x³ - 1
Step-by-step explanation:
Substitute x = g(x) into f(x), that is
(f ○ g)(x)
= f(x³ )
= - 6(x³) - 1
= - 6x³ - 1
B. Y equals 0, because if you plug it in ( multiply 2 by 9 ) you will get 18-18 which equals 0.
1. the image is multiplied by the scale factor. if the scale factor is 2, the image is twice the size of the preimage. if the scale factor is ⅓, the image is one third the size. only a scale factor of 1 preserves congruency