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marta [7]
3 years ago
10

Given F1 = ∑ m(0,2,5,7,9) and F1 = ∑ m(2, 3,4,7,8) find the minterm expression for F1+F2. State a general rule for finding the e

xpression for F1+F2 given the minterm expansions for F1 and F2. Prove your answer by using the general form of the minterm expansion.

Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0

Answer:

Step-by-step explanation:

The question tells us that;

Given F1 = ∑ m(0,2,5,7,9) and F1 = ∑ m(2, 3,4,7,8) find the minterm expression for F1+F2. State a general rule for finding the expression for F1+F2 given the minterm expansions for F1 and F2. Prove your answer by using the general form of the minterm expansion.

Note: The answer is provided in the image uploaded below

cheers i hope this helped !!!

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Graphing Natural Exponential Functions In Exercise, sketch the graph of the function.
strojnjashka [21]

Answer:

Step-by-step explanation:

Graph:  f(x) = 1 - ex

You meant f(x) = 1 - e^x, where ^ represents exponentiation.

First, graph the parent function y = e^x.  The y-intercept of this graph is (0, 1), and the x-axis is the horizontal intercept.  The graph begins on the left in Quadrant 2 and continues upward in Quadrant 1.

Next, reflect this graph in the x-axis, due to the - sign in f(x) = 1 - e^x.  The y-intercept is (0, -1) and the horizontal asymptote is the x-axis.

Finally, translate the whole graph upward by 1 unit.

5 0
3 years ago
In the circle below, DB = 22 cm, and m&lt;DBC = 60°. Find BC. Ignore my handwriting.​
Karo-lina-s [1.5K]

Answer:

BC=11\ cm

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

m\angle DBC=\frac{1}{2}[arc\ DC]

substitute the values

60\°=\frac{1}{2}[arc\ DC]

120\°=arc\ DC

arc\ DC=120\°

step 2

Find the measure of arc BC

we know that

arc\ DC+arc\ BC=180\° ----> because the diameter BD divide the circle into two equal parts

120\°+arc\ BC=180\°

arc\ BC=180\°-120\°=60\°

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

m\angle BDC=\frac{1}{2}[arc\ BC]

substitute the values

m\angle BDC=\frac{1}{2}[60\°]

m\angle BDC=30\°

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

sin(\angle BDC)=BC/BD

BC=(BD)sin(\angle BDC)

substitute the values

BC=(22)sin(30\°)=11\ cm

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3 years ago
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Answer:

The answer is 18.75

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