Answer:
By the Empirical Rule, 99.7% of the students have grade point averages that are between 1.28 and 3.8.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 2.54
Standard deviation = 0.42.
Between 1.28 and 3.8?
1.28 = 2.54 - 3*0.42
So 1.28 is 3 standard deviations below the mean
3.8 = 2.54 + 3*0.42
So 3.8 is 3 standard deviations above the mean
By the Empirical Rule, 99.7% of the students have grade point averages that are between 1.28 and 3.8.
Hi there!
The formula for the volume of a sphere is V = 4/3(pi)(r^3). Using this formula, we can plug in what we know and solve.
WORK:
V = 4/3(pi)(10^3)
V = 4/3(1000pi)
V = 4000pi/3 or 1333.3 pi
V also = 4188.8
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
(a) V = 51200 cubic cm
(b) V' = 38912 cubic cm
(c) V'' = V - V' = 12288 cubic cm
Step-by-step explanation:
side of the square base, s = 32 cm
height, h = 50 cm
height of cake mixture, h' = 38 cm
(a) The capacity of the tin is the volume.
Capacity of tin, V = s x s x h = 32 x 32 x 50 = 51200 cubic cm
(b) The volume of the cake mixture is
V' = s x s x h'
V' = 32 x 32 x 38 = 38912 cubic cm
(c) Volume of unoccupied space is
V'' = V - V' = 51200 - 38912 = 12288 cubic cm
Answer:
9090 kilograms
Step-by-step explanation:
To find the number of kilograms per dragon, we divide the amount of meat by the number of dragons.
4545/22 kilograms per dragon
Now we can multiply by the 44 dragon that she has.
4545/22 * 44 = 9090 kilograms
