Answer:
x = -3
Step-by-step explanation:
10(x-5) = -80
10x - 50 = -80
10x -50 + 50 = -80 + 50
10x = -30
10x ÷ 10 = -30 ÷ 10
x = -3
Let
denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position

and velocity

Immediately after launch, the rocket is subject to gravity, so its acceleration is

where
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,


(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

and



b. The rocket stays in the air for as long as it takes until
, where
is the
-component of the position vector.

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

c. The rocket reaches its maximum height when its vertical velocity (the
-component) is 0, at which point we have


D) i think
, all values of x that are greater than equal to 1
7
8
Answer:
no solution
Step-by-step explanation:
Given
3(x - 3) = 3x , that is
3x - 9 = 3x ( add 9 to both sides )
3x = 3x + 9 ( subtract 3x from both sides )
0 = 9 ← not possible
This indicates the equation has no solution
Answer:
the answer would be 2(2+11)
Step-by-step explanation: