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3 years ago

11

You lose 5 points for every wrong answer in trivia game. What integer represents the change in your points after answering 8 que

stions wrong?

1 answer:

salantis [7]3 years ago

3 0

-5 * 8 = -40 losing would make your number be multiplied by the points lost each time

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The phone company A Fee and Fee has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount o

IgorLugansk [536]

Answer:

y=0.2x+29

Step-by-step explanation:

Given that:

y is the total monthly of the A Fee and Fee plan.

x is the number of monthly minutes used.

If a customer uses 290 minutes, the monthly cost will be $87, we have the pair (290, 87)

If the customer uses 980 minutes, the monthly cost will be $225, this is the coordinate pair (980, 225).

We want to obtain an equation in the form: y=mx+b

First, let us determine the slope, m

Given points (290, 87) and (980, 225):

<u>Slope</u>

$m=\dfrac{225-87}{980-290} =\dfrac{138}{690}=0.2$

Next, we determine the y-intercept, b.

Substituting the pair (290, 87) and m=0.2 in y=mx+b, we obtain

87=0.2(290)+b

b=87-0.2(290)=29

Therefore, our equation in the form y=mx+b is:

y=0.2x+29

8 0

3 years ago

Suppose it is known that the distribution of purchase amounts by customers entering a popular retail store is approximately norm

iragen [17]

Answer:

a. 0.691

b. 0.382

c. 0.933

d. $88.490

e. $58.168

f. 5th percentile: $42.103

95th percentile: $107.897

Step-by-step explanation:

We have, for the purchase amounts by customers, a normal distribution with mean $75 and standard deviation of $20.

a. This can be calculated using the z-score:

$z=\dfrac{X-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\P(X$

The probability that a randomly selected customer spends less than $85 at this store is 0.691.

b. We have to calculate the z-scores for both values:

$z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{65-75}{20}=\dfrac{-10}{20}=-0.5\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\\\P(65$

The probability that a randomly selected customer spends between $65 and $85 at this store is 0.382.

c. We recalculate the z-score for X=45.

$z=\dfrac{X-\mu}{\sigma}=\dfrac{45-75}{20}=\dfrac{-30}{20}=-1.5\\\\\\P(X>45)=P(z>-1.5)=0.933$

The probability that a randomly selected customer spends more than $45 at this store is 0.933.

d. In this case, first we have to calculate the z-score that satisfies P(z<z*)=0.75, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

$P(z$

Then, we can calculate X as:

$X^*=\mu+z^*\cdot\sigma=75+0.67449\cdot 20=75+13.4898=88.490$

75% of the customers will not spend more than $88.49.

e. In this case, first we have to calculate the z-score that satisfies P(z>z*)=0.8, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

$P(z>-0.84162)=0.80$

Then, we can calculate X as:

$X^*=\mu+z^*\cdot\sigma=75+(-0.84162)\cdot 20=75-16.8324=58.168$

80% of the customers will spend more than $58.17.

f. We have to calculate the two points that are equidistant from the mean such that 90% of all customer purchases are between these values.

In terms of the z-score, we can express this as:

$P(|z|$

The value for z* is ±1.64485.

We can now calculate the values for X as:

$X_1=\mu+z_1\cdot\sigma=75+(-1.64485)\cdot 20=75-32.897=42.103\\\\\\X_2=\mu+z_2\cdot\sigma=75+1.64485\cdot 20=75+32.897=107.897$

5th percentile: $42.103

95th percentile: $107.897

5 0

3 years ago

HELPPP PLEASE WILL NAME BRAINLIEST

laila [671]

The first reaction represented is a decomposition reaction due to the fact the bonded pair are being split apart.

The second equation is a single displacement because the B and C have switched places, which is the only change making it a single displacement. If there had been another bond and A had also moved, it would be double.

7 0

3 years ago

Read 2 more answers

Plz help me answer this!!!

larisa86 [58]

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

c=1/4

Decimal Form:

c=0.25

8 0

3 years ago

In 2011, a U.S. Census report determined that 71% of college students work. A researcher thinks this percentage has changed sinc

coldgirl [10]

Answer:

Note: The full question is attached as picture below

a) Hо : p = 0.71

Ha : p ≠ 0.71

<em>p </em>= x / n

<em>p </em>= 91/110

<em>p </em>= 0.83.

1 - Pо = 1 - 0.71 = 0.29.

b) Test statistic = z

= <em>p </em>- Pо / [√Pо * (1 - Pо ) / n]

= 0.83 - 0.71 / [√(0.71 * 0.29) / 110]

= 0.12 / 0.043265

= 2.77360453

Test statistic = 2.77

c) P-value

P(z > 2.77) = 2 * [1 - P(z < 2.77)] = 2 * 0.0028

P-value = 0.0056

∝ = 0.01

P-value < ∝

Reject the null hypothesis. There is sufficient evidence to support the researchers claim at the 1% significance level.

6 0

3 years ago