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jeyben [28]
2 years ago
15

A 2000 kilogram sports car accelerates at a ratr of 30 meters per second squared. The velocity of the car is v=at where a is acc

eleration in meters per second squaref and t is tome in seconds. The kinetic energy of the car is KE = 1/2 mv^2
Mathematics
2 answers:
solniwko [45]2 years ago
8 0

Answer:

KE = 900,000t²

Step-by-step explanation:

The formula for calculating the kinetic energy of a body is expressed as KE = 1/2mv² where;

m is the mass of the sport car = 2000kg

v is the velocity of the car

Since v = at

v = 30t

Substituting the given values into the KE formula;

KE  1/2 * 2000 * (30t)²

KE = 1000*900t²

KE = 900,000t² Joules where t is the time measured in seconds

mestny [16]2 years ago
4 0

Answer:

KE = 900,000t²

Step-by-step explanation:

Answer is D if you use edgenuity, answers do not mix

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8m-4=16

8m=20

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Students were surveyed about what summer camp they would be attending.
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5% with the information I'm provided with. I need more info

if that's wrong

Step-by-step explanation:

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These are expression written as a function of sine, cosine and tangent. The value of x from the given function is 4.29

Trigonometry expression

These are expression written as a function of sine, cosine and tangent.

Given

tanx² - 1/3 = 0

Add 1/3 to both sides

tanx² - 1/3 + 1/3 = 0 + 1/3

tanx² = 1/3

x² = arctan(1/3)

x² = 18.44

x =4.29

Hence the value of x from the given function is 4.29

Learn more on trig function here: brainly.com/question/24349828

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6 0
1 year ago
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A community bird-watching society makes and sells simple bird feeders to raise money for its conservation activities. The materi
blondinia [14]

Answer:

The required function is: P(x)=-3x^2+78x-360

The price for each feeder to maximize profit should be $13.

The maximum weekly profit is $147

Step-by-step explanation:

Consider the provided information.

Part (A)

The materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each.

Let x be the price per feeder.

Profit = Revenue - cost

So the profit per feeder is x-6

If we increase then for every dollar increase, it loses 3 sales per week.

This can be written as:

30-3(x-10)

30-3x+30

-3x+60

Where x-10 represents the increase in price and 3  represents the decrease in sales per week.

Thus the profit will be:

P(x)=(x-6)(-3x+60)

P(x)=-3x^2+78x-360

Hence, the required function is: P(x)=-3x^2+78x-360

Part (B) What price should the society charge for each feeder to maximize profits? What is the maximum weekly profit?

The above function is a downward parabola so the maximum will occur at vertex.

The x coordinate of the vertex of parabola is: x=\frac{-b}{2a}

Substitute a=-3, b=78 and c=-360 in above.

x=\frac{-78}{2(-3)}=13

Hence, the price for each feeder to maximize profit should be $13.

Now substitute the value of x in P(x)=-3x^2+78x-360

P(x)=-3(13)^2+78(13)-360=$147

Hence, the maximum weekly profit is $147

5 0
2 years ago
Solve the equation: 3(x - 2) = 36<br><br><br><br><br> X=-5<br> X=14<br> X=10<br> X=5
Paul [167]
3(x-2)=36
3x-6=36
3x=36+6
3x=42
x=42/3
x=14
Answer: 14
I hope this helped mate!
8 0
3 years ago
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