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3 years ago

I need help with b and question 10 (all parts) HELP PLEASE URGENT

Mathematics

1 answer:

lana66690 [7]3 years ago

7 0

In part b) you are asked to find the area of the compound figure. I see you have already split the figure into two rectangles, which is correct.

To find the area of a rectangle use length times width.

Left rectangle: 33 ft * 10 ft = 330 ft^2

Right rectangle: 30 ft * 25 ft = 750 ft^2

Add the areas together: 330 + 750 = 1,080 ft^2

In question 10, you are asked to find the surface area of the rectangular prism.

You are given the formula for the SA, p * h + 2B.

p = perimeter of base, h = height, B = area of base

168 * 68 + 2(1,764) = 14,952 mm^2

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Without multiplying determine whether the product of 5 x 4/5 is located on the number line at point A,B or C

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4 years ago

Multiply (3x-2)(2x+6)

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3 years ago

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Find the 44th percentile, P44, from the following data! pls help

irina [24]

Answer:

$P_{44} = 29.9$

Step-by-step Explanation:

The 44th percentile, $P_{44}$ , of the given data can be calculated using the kth formula for percentile given as:

$i = \frac{k}{100}(n + 1)$

where,

i = the ranking or the position of the percentile = ?

k = the percentile = 44

n = total number of the given data values = 23

Plug in the values into the formula to find "i"

$i = \frac{44}{100}(23 + 1)$

$i = \frac{44}{100}(24)$

$i = \frac{1,056}{100}$

$i = 10.56$

Since "I", 10.56, is not an integer, round the number down, and round it up to the nearest integer, then look for the position each occupy in the ordered data set, and find their average.

Thus,

$i_{down} = 10.56 = 10$

$i_{up} = 10.56 = 11$

The data occupying the 10th position on the data set = 28.7

11th = 31.1

$P_{44} = \frac{28.7 + 31.1}{2} = \frac{59.8}{2}$

$P_{44} = 29.9$

6 0

3 years ago

Riley makes a mistake in step 2 while doing her homework. What was her mistake? StartFraction x Over x squared minus 5 x + 6 End

kobusy [5.1K]

Answer:

The answer is:

She used the wrong common denominator

Step-by-step explanation:

Solving the given equation

$\frac{x}{x^2-5x+6}+\frac{x}{x+3}\\\\Step 1: \frac{x}{(x-2)(x-3)}+\frac{x}{x+3}\\Step2: \frac{x}{(x-2)(x-3)}+\frac{x(x-2)}{(x-2)(x+3)}\\Step3:\frac{x(x+3)+x(x-2)(x+3)}{(x-2)(x-3)(x+3)}$

Lets consider the steps given in the question:

$Step2: \frac{x}{(x-2)(x+3)}+\frac{3(x-2)}{(x-2)(x+3)}$

$Step3: \frac{x+3(x-2)}{(x-2)(x+3)}\\$

Lets compare both solutions:

In the original solution, the denominator of first term is (x-2)(x-3)

In the solution given in the question, the denominator of first term is (x-2)(x+3).

So the mistake she did in step 2 was that she change the sign of 3 in (x-3) from negative to positive, due to which she gets the wrong common denominator shown in Step 3.

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4 years ago

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