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chubhunter [2.5K]
2 years ago
15

How many different arrangements can be made with the letters from the word topic? 24 120 3,125 10?

Mathematics
1 answer:
Gala2k [10]2 years ago
5 0
I believe its 24 but i may be wrong
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The product of 2 and 8 divided by 8 is equal to?
ASHA 777 [7]

Answer:

2

Step-by-step explanation:

product of 2 and 8= multiply

2x8=16

Divide by 8

16/8=2

6 0
3 years ago
Read 2 more answers
What is the sum of the two vectors (-1,-4) and (3,5)
o-na [289]

Answer:

Step-by-step explanation:

a(-1, -4)\\b(3, 5)\\a + b(2, 1)

5 0
3 years ago
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There are n apples in a box; this is 3/7 of all the fruits in it. How many fruits are there in the box? (n=21)
Morgarella [4.7K]

Answer:

49

Step-by-step explanation:

n is 3/7 of total fruit

n=21 apples

Here they are just telling us that the apples make up a total of 3/7 percent of the total fruit in the box. So to find the total amount of fruit from this information we just simply take the n number of apples and divide that by the percent that it represents. So basically just this;

n=21 and (n)/(3/7)=total fruit

(21)/(3/7)=21*7/3=147/3=49 total fruit and 21apples make up (3/7)% of the total fruit in the box.

Hope this helped some. Any questions please feel free to ask. Thanks!

4 0
3 years ago
What is the value of x?
Talja [164]
Use the Pythagorean theorem. The Pythagorean Theorem uses the following formula:

a^{2} + b^{2} = c^{2}

Plug in the known values into the equation:

a = 6, c = 10

6^{2} + b^{2} = 10^{2}

36 + b^{2} = 100

Subtract both sides by 36.

b^{2} = 64

Square root both sides to get b by itself.

\sqrt{64} = 8

b = 8

The value of x is 8.
7 0
3 years ago
Read 2 more answers
a 34 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.137. find the substance's half-life, i
Ira Lisetskai [31]

Answer:

5.1 days

Step-by-step explanation:

Given in the question,

initial amount of substance = 34 grams

k-value = 0.137

To find the half life of this substance we will use following formula

N(0)/2 = N(0)e^{-kt}

here N(0) is initial amount of substance

        t is time in days

Plug values in the formula

34 /2 = 34e^{-0.137t}

1/2 = e^{-0.137t}

Take logarithm on both sides

ln(1/2) = ln( e^{-0.137t})

ln(1/2) = -0.137t

t = ln(1/2) / -0.137

t = 5.059

t ≈ 5.1 days (nearest to tenths)

3 0
3 years ago
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