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Sonbull [250]
3 years ago
6

spends 2 hours and 20 minutes trading stickers and 125 minutes doing homework. What activity does he spend more time on? How muc

h more time?
Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0
Answer: He spends more time trading stickers by 15 minutes.
Step-by-step: 1 hour is 60 minutes. So 2 hours is 120 minutes. 120 minutes plus his 20 minutes is 140 minutes. Subtract it from his homework time and he spends 15 more minutes trading stickers.
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Incomplete question, check attachment for the necessary diagram

Step-by-step explanation:

Note in the attachment,

We have two identical straight line of lenght

L1 = L2 = 84.39m

We also have two identical semicircle or radius 36.5m to the first track lane

But this is not the radius of the circle, the radius of the circle will now be 36.5 plus the 6 track lane and we are told that one track lane is 1m, then, the track lane is 6m

So, radius = 36.5+6

r = 42.5m

Then, we need to calculate the perimeter of the semicircle using the formula of perimeter of a circle and dividing by2

P = 2πr/2

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P = 22/7 × 42.5

P = 133.57 m

Then, the arc 1 is equal to arc 2 which is equal to 133.57 m

A1 = A2 = 133.57 m

Now we have all the dimensions,

Then, the perimeter can be calculated by adding the length of the sides

The perimeter of the field = Lenght of the two straight lines plus the length of the two semicircle arc

P = L1 + L2 + A1 + A2

P = 84.39 + 84.39 + 133.57 + 133.57

P =435.923 m

So, to the nearest meter

P ≈ 436m

The perimeter of the track is 436m

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Step-by-step explanation:

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