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4 years ago

How do you solve -10+2y=7

Mathematics

1 answer:

Eva8 [605]4 years ago

5 0

Answer

y = $\frac{17}{2}$

Step-by-step explanation:

-10 + 2y = 7

Add 10 to both sides of the equation

2y = 7 + 10

Add 7 and 10

2y = 17

divide each term in 2y=17 by 2

$\frac{2y }{2} = \frac{17}{2}$

Divide y by 7

y = $\frac{17}{2}$

Hope this helps

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Answer:

28,125

Step-by-step explanation:

There are 10 digits between 0 and 9. 5 of them are odd, and 5 of them are even.

If a six-digit number has all odd digits, then there are 5 numbers that can be the first digit, 5 numbers that can be the second digit, 5 numbers that can be the third digit, and so on.

The number of permutations is 5×5×5×5×5×5 = 5⁶ = 15,625.

For all even digit numbers, the first digit can't be 0, so the number of permutations is 4×5×5×5×5×5 = 4×5⁵ = 12,500.

So the total permutations of six-digit numbers of equal parity is 15,625 + 12,500 = 28,125.

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