Consider an election with 681 votes a) If there are 5 candidates, what is the smallest number of first-place votes a candidate c
ould win with under the Plurality method?
1 answer:
Answer:
137 votes
Step-by-step explanation:
considering an election with 681 votes and 5 candidates up for the election
dividing the votes among'st 5 candidates
= 681 / 5 = 136.2 hence the least number of first-place votes needed by a candidate using the plurality method would be = 137 votes
136.2 + 136.2 + 136.2 + 136.2 + 136.2 = 681 ( dividing the votes equally )
136 + 136 + 136 + 136+136 = 680
hence the remaining vote = 681 - 680 = 1
least first-place vote = 136 + 1 = 137 votes
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Answer:
60 degrees
Step-by-step explanation:
Answer:
1/ x = 22.5°
2/ x = 60°
Step-by-step explanation:
1/ We have: 3x + 2x + 3x = 180°
=> 8x = 180° => x = 22.5°
2/ We have: x + x + x = 3x = 180°
=> x = 60°
4(2x5 + 3) - 4(2) + 2(5).
4(13) - 18.
52-18 = 34.
a= 6-2b-3c
then put that equation inside the first one and then the second one
you get -6*(6-2b-3c)+2b-3c=23
and 5*(6-2b-3c)+4b-3c=-12
14b-15c=59
14b-18c=18/*(-1)
--------------------
3b=41
Answer: -5 1/2 or -5.5
Step-by-step explanation: Negative five and a half. Its technically -5 2/4 but simplify 2/4 its 1/2
