Consider an election with 681 votes a) If there are 5 candidates, what is the smallest number of first-place votes a candidate c

Question

3 years ago

6

ould win with under the Plurality method?

1 answer:

joja [24] · Answer 1 · 2022-01-27T06:29:14+03:00

Answer:

137 votes

Step-by-step explanation:

considering an election with 681 votes and 5 candidates up for the election

dividing the votes among'st 5 candidates

= 681 / 5 = 136.2 hence the least number of first-place votes needed by a candidate using the plurality method would be = 137 votes

136.2 + 136.2 + 136.2 + 136.2 + 136.2 = 681 ( dividing the votes equally )

136 + 136 + 136 + 136+136 = 680

hence the remaining vote = 681 - 680 = 1

least first-place vote = 136 + 1 = 137 votes