Answer:
No. It is a constant function.
Step-by-step explanation:
The function f(x) = e^2 is not an exponential functional. Rather, it is a constant function. The reason for this is that in f(x) = e^2, there is no x involved on the right hand side of the equation. The approximate value of e is 2.718281, and the approximate value of 2.718281^2 is 7.389051. This means that f(x) = e^2 = 7.389051. It is important to note that for any value of x, the value of the function remains fixed. This is because the function does not involve the variable x in it. The graph of the function will be a line parallel to the x-axis, and the y-intercept will be 7.389051. For all the lines parallel to x-axis, the value of the function remains the same irrespective of the value of x. Also, the derivative of the function with respect to x is 0, which means that the value of the function is unaffected by the change in the value of x!!!
1. P = 2(9) + 2(4.5)
P = 18 + 9
P = 27 m
2. P = 5.2(2) + 1.3(2)
P = 10.4 + 2.6
P = 13 ft
3. P = 12.9(2) + 4.7(2)
P = 25.8 + 9.4
P = 35.2 cm
Answer:
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Step-by-step explanation:
Answer:
πr² is the area of a circle
First, we have that the generic equation of the line is given by:
y-yo = m (x-xo)
Substituting values we have:
y - (- 14) = - 2 (x-0)
Rewriting:
y + 14 = -2x
y = -2x - 14
Answer:
The equation of the line written in its slope-intercept form is given by:
y = -2x - 14
