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svlad2 [7]
3 years ago
10

Expand than simplify: -4(-2p+5)

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0
First what we do since we are expanding the expression is do

-4*-2p
=8p

Then,

-4*5
=-20

Now since there are no like terms we get our final answer which is...

*8p-20*
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RUDIKE [14]
According to the diagram the answer is 36degree
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1 year ago
What properties of equality do you need to use to solve the equation 5.6x−16.9=−0.1​? Solve the equation
kakasveta [241]

Answer:

5.6x-16.9=-0.1

28x/5-16.9=-0.1

28x/5-16.9=-0.1

28x/5-16.9+16.9=-0.1+16.9

28x/5=16.8

x=3

Step-by-step explanation:

6 0
3 years ago
Earl when to the store and realize he had 7 more Nickles in his pocket then he thought he had. If all the change in earl’s pocke
Feliz [49]

Answer:

40 nickles

Step-by-step explanation:

Here is the correct question: Earl went to the store and realize he had 7 more Nickles in his pocket then he thought he had; If all the change in earl’s pocket is nickles, he had $2.35 in his pocket, how many more nickles did he think were in his pocket ?

Given: All Nickles in the Earl´s pocket is $2.35.

Remember, 1 Nickles = $.05

∴ Converting the dollar to nickels

$2.35= \frac{\$ 2.35}{\$ .05} = 47 \ nickels

Earl had total 47 nickels in his pocket.

∴ Earl earlier had nickles = 47-7= 40 \ nickles

∵ we know Earl had realized that he had 7 more nickles in his pocket, which means he already had 40 nickles to make $2.35.

4 0
3 years ago
Which deal on notebooks is the best 20 for $8 or 30 for $10
WARRIOR [948]
30 for 8 because for 2$ more you can have 10
3 0
3 years ago
Read 2 more answers
Which of the following choices lists the correct values of a,h, and k for the function f(x)=5x^2
Tju [1.3M]

Answer:

For a general quadratic equation like:

y = a*x^2 + b*x + c

a is the leading coefficient.

And we define the vertex of this as (h, k)

Where h is:

h = -b/(2*a)

and k is the y-value given when we use x = h.

Now, in this case we have:

f(x) = 5*x^2

We can see that the leading coefficient is 5, then a = 5.

To find the value of h we use:

h = -b/(2*a)

there is no lineal term, thus b = 0, then:

h = -0/(2*5) = -0/10 = 0

and k is given by

f(h) = f(0) = 5*0^2 = 0

then k = 0.

Concluding:

a = 5

h = 0

k = 0

8 0
3 years ago
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