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Bogdan [553]
3 years ago
8

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0

\bf{Hey\ there!}

\bf{Quadratic\ formula\ is:}\bf{x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}} \ or \ you\ could\ say\ ax^2+bx+c=0

\bf{\bullet\ First: subtract\ by\ 2x\ on\ your\ sides\ that\ you're\ working\ with}

\bf{Like:x^2+20-2x=2x-2x}

\bf{We\ get:x^2-2x+20=0}

\bf{\bullet \ a=1}\\ \bf{\bullet \ b=-2}\\ \bf{\bullet \ c=20}

\bf{x=\frac{-(-2)\pm\sqrt{(-2)^2-4(1)(20})}{2(1)}

\bf{(-2)^2-4(1)(20)=-76} \\ \\ \bf{2(1)=2}

\bold{-(-2)=-1(-2))=+2}

\bf{x=\frac{2\pm\sqrt{-76}}{2}}

\bf{Thus\ there\ is\ NO\ REAL\ SOLUTIONS}

\text{Good\ luck\ on\ your\ assignment\ and\ enjoy\ your\ day!}

\frak{LoveYourselfFirst:)}

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