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2 years ago

I need help due by tomorrow

Mathematics

2 answers:

Bezzdna [24]2 years ago

8 0

Answer:

circumference =3.14 ×13 and It comes 40.82

Step-by-step explanation:

c=3.14 ×d

and d=13 so substitute it and it will be

c=3.14 ×13=40.82

Flauer [41]2 years ago

6 0

Can you tell me the options first and the formula C=Y

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If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that the d

katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Sample size needed

At least n, in which n is found when $M = 0.09$

We don't know the proportion, so we use $\pi = 0.5$ , which is when we would need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.09\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.09}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}$

$n = 118.6$

Rounding up

We need a sample size of least 119

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3 years ago

You are gathering data in the store, recording which shirt is tried on the most. The data you gather is... A) bivariate B) categ

borishaifa [10]

Answer:

(D) Quantitative

Step-by-step explanation:

Bivariate data involves two types of variables. Categorical data will have a number of different categories. Continuous data usually includes a range of values so is likely to be in decimals. Quantitative data will be collected in this scenario as it will be calculated the number of times each shirt is tried on.

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3 years ago

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2 years ago

Read 2 more answers

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