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Margaret [11]
3 years ago
8

What's the answer to the highlighted questions? Also how would you draw the diagram?

Mathematics
2 answers:
Basile [38]3 years ago
8 0
Question 3 is 10. question 4 is also 10.
slamgirl [31]3 years ago
6 0
You would draw a diagram for this by splitting a bar into the number of the denominator e.g. 4/5 (you would split it into 5 then colour in four) hope it helps you visualise it :)

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Suppose a student visited 81 websites while conducting research. If 9 of the websites were "us.gov" websites, what percentage of
rjkz [21]

Answer:

9/81 or 1/9 = .1111111111R

Step-by-step explanation:

It is that because that is the decimal and 9 goes into 9 once and 9 goes into 81 nine times

3 0
3 years ago
Which expression is equivalent to 4+6(ac+2b)+2ac
Montano1993 [528]

Answer: 8ac+12b+4

Step-by-step explanation: Simplify the expression.

Hope this helps you out! ☺

7 0
3 years ago
Harper is knitting a scarf for her cousin's birthday. She plans to knit every night, making the scarf 5 centimeters longer each
MissTica

The equation that shows the relationship between x and y is:

y = 5x

A linear equation is in the form:

y = mx + b

where m is the rate of change and b is the initial value of y, y, x are variables.

Let x represent the number of nights knitting and y represent the length of the scarf.

The equation that shows the relationship between x and y is:

y = 5x

Find out more at: brainly.com/question/13911928

8 0
3 years ago
Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
4 years ago
Y-12=4y solve for y and show work plz
Katena32 [7]
First, you want to start by subtracting y from each side to get it isolated. After that, your equation should be
3y= -12
Then, divide each side by 3 to isolate the y. You should end up with y= -4
7 0
3 years ago
Read 2 more answers
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