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Margaret [11]
3 years ago
8

What's the answer to the highlighted questions? Also how would you draw the diagram?

Mathematics
2 answers:
Basile [38]3 years ago
8 0
Question 3 is 10. question 4 is also 10.
slamgirl [31]3 years ago
6 0
You would draw a diagram for this by splitting a bar into the number of the denominator e.g. 4/5 (you would split it into 5 then colour in four) hope it helps you visualise it :)

You might be interested in
7. A coin is tossed and a day of the week is selected. What is the probability that you get tails and a day that begins with "S"
Mrrafil [7]

Answer:

1/7

Step-by-step explanation:

Lets start with the probability of flipping tails, 1/2.

Then the probability of the day starting with the letter s, 2/7.

Calculate the final probability by multiplying the two together.

\frac{1}{2}*\frac{2}{7}=\frac{2}{14}

You can simplify 2/14 down to 1/7

6 0
2 years ago
On a biased dice , the probability of getting a 6 is 4/5. The dice is rolled 500 times. How many sixes would you expect to roll?
tatyana61 [14]

Find 4/5 of 500.

4/5*500=400

You will roll 400 sixes.

5 0
3 years ago
a bean plant was 15 centimeters tall one week ago. In 5 days it grew 1 meter. find the current height of the plant.
Likurg_2 [28]
The plant is currently 115 centimeters high
4 0
4 years ago
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
Find the length of side x in simplest radical form with a rational a<br> denominator.
geniusboy [140]

Step-by-step explanation:

the answer is

x =  \sqrt{3}

5 0
3 years ago
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