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Oksi-84 [34.3K]
3 years ago
6

Name three pairs of numbers that have 5 as their gfc (Greatest Common factor). Use each number once in your answer. I really nee

d help asap. Thanks! (:
Mathematics
2 answers:
katen-ka-za [31]3 years ago
4 0
20,25 and 35,50 and 10,15. Each pair would have a GCF of 5.
Fed [463]3 years ago
3 0
Any three numbers that are multiples of 5 can be your answer. i would use 5 10 and 15
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What effect would doubling all the dimensions of a triangular pyramid have on the volume of the pyramid?
lana66690 [7]

Answer:

The effect of doubling all the dimensions of a triangular pyramid will have on the volume of the pyramid is to increase it by 8 times.

Step-by-step explanation:

i) volume of triangular pyramid  = \frac{1}{3} \times Area \times height

     = \frac{1}{3} \times (Base of triangle \times perpendicular height of triangle) \times height

ii) if we double all the dimensions then the three variables((Base of triangle, perpendicular height of triangle, height of pyramid) will be doubled

  and the volume of the new pyramid will be 8 times that of the original one.

3 0
3 years ago
Please help me asap
Yuliya22 [10]

Answer:

2) 25%

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The sum of 3 consecutive integers is 45
nekit [7.7K]
The answer is going to be 14 15 16

14+15+16 = 45
6 0
4 years ago
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It’s about right triangles but it’s confusing
Lynna [10]

Answer:

A

Step-by-step explanation:

Use Pythagorean Theorem, which is for side lengths of right triangles.

a^2 + b^2 = c^2  (c is the hypotenuse)

Common combination is 3-4-5. Just by looking at the answers, I can see A is 3-4-5 except everything is multiplied by 2.

B is wrong. It would be 5-12-13 if it were a RT.

C is wrong. 3-4-5

D is wrong. 4 + 25 = 49 is not an equation.

3 0
4 years ago
Read 2 more answers
A quiz has twenty questions with 7 points awarded for each correct answer, 2 points deducted for each wrong answer and 0 for eac
alexandr1967 [171]
<h3>Answer: Jack skipped 5 questions</h3>

(he got 2 wrong answers, and 13 correct answers)

=====================================================

Explanation:

c = number of correct answers

w = number of wrong answers

m = number of missing answers (ie, omitted answers)

7c = number of points awarded from just the correct answers

-2w = number of points awarded from the wrong answers. Note the negative to indicate we lose points here.

0m = 0 = points from the missing answers. We don't have to worry about this portion

In total, Jack would earn 7c-2w points. Since he actually earned 87 points, we can write the equation 7c-2w = 87. We'll come back to this later.

-----------------------

The quiz has 20 questions, so c+w+m = 20 is another equation we'll be working with. Solve for c to get c = -w-m+20. Plug this into the equation 7c-2w = 87 to get...

7c-2w = 87

7(-w-m+20)-2w = 87 ... replace c with (-w-m+20)

-7w-7m+140-2w = 87 ... distribute

-9w-7m+140 = 87

-9w-7m = 87-140

-9w-7m = -53

9w+7m = 53

----------------------

From here, you use trial and error. We don't have enough information to finish solving the system. We would need 3 equations to solve for the 3 unknowns.

What we can do is make a guess of what w could be and use that to find m. Luckily there is a small list of possible values for w.

So let's say w = 0

9w+7m = 53

9(0)+7m = 53 ... plug in w = 0

7m = 53

m = 53/7 ... divide both sides by 7

m = 7.57

We got a non-whole number, so there is no way w = 0 since we can't have 0.57 of a question missing. Jack either answers the question, or he skips it. He can't have both happen.

---------------------

Let's repeat for w = 1

9w+7m = 53

9(1)+7m = 53 ... replace w with 1

9+7m = 53

7m = 53-9 ... subtract 9 from both sides

7m = 44

m = 44/7 ... divide both sides by 7

m = 6.28

So we can see that w = 1 isn't possible either.

---------------------

However, w = 2 is possible

9w+7m = 53

9(2)+7m = 53

18+7m = 53

7m = 53-18

7m = 35

m = 35/7

m = 5

Meaning that Jack got w = 2 wrong answers and skipped over m = 5 questions. The number of correct answers is c = 20-m-w = 20-5-2 = 13

-----------------------------------

An alternative to using trial-and-error is to use a graph.

Replace w and m with x and y respectively. So we go from 9w+7m = 53 to 9x+7y = 53

Use a graphing tool, or plot the graph on graph paper, to get what you see in the diagram below. I used the program GeoGebra to graph.

Then notice how the graph goes through the point (2,5) which means x = 2 and y = 5. Replace x and y with w and m to find (w,m) = (2,5)

note: the point (5,1) looks like it also lies on the graph, but it is not a solution. It's just a point that is very close to the line. I recommend you try out (w,m) = (5,1) and you'll see it doesn't work.

3 0
3 years ago
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