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4 years ago

Veronica ran 1.5 times around a 2.05 mile beach track. How far did she run? Your newer

Mathematics

1 answer:

Butoxors [25]4 years ago

3 0

Answer:

Veronica ran 3.075 miles.

Step-by-step explanation:

In order to find how far Veronica ran, we'll have to multiply the amount of times she ran around the track by the length of the track.

1.5 * 2.05 = 3.075

You can leave the answer as is or round it to 3.1

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Use the inverse of the function y = x2 − 18x to find the unknown values.

Lerok [7]

ANSWER

b=1, c=81, and d=9.

EXPLANATION

The given function is:

$y={x}^{2}-18x$

This function is the same as:

$y={(x - 9)}^{2}-81$

To find the inverse of this function, we interchange x and y.

$x={(y-9)}^{2}-81$

Solve for y:

$x+81={(y- 9)}^{2}$

Take square root of both sides:

$\pm \sqrt{x + 81}=y-9$

$y=\pm \sqrt{x + 81}+9$

Hence,

b=1, c=81, and d=9.

7 0

3 years ago

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Please help!!!!!! + lots of points

Ilya [14]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~

The correct answers are A, B, D, and E

4 0

3 years ago

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Select the equation where x = 6 is a solution.

olga55 [171]

Answer: D 5x=30

Step-by-step explanation

You just substitute 6 into the equations to see if they make the equation true.

8 0

3 years ago

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8. It took Lisa 20 minutes to change 2 tires on a car. If she works at the same rate,

Ad libitum [116K]

Answer:

40 minutes

Step-by-step explanation:

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3 years ago

Suppose that your boss must choose three employees in your office to attend a conference in Jamaica. Because all 17 of you want

Pani-rosa [81]

Answer:

$P(You\ n\ Anna\ n\ Kevin) = \frac{1}{4913}$

Step-by-step explanation:

Given

$Total\ Employees = 17$

$To\ Select = 3$

Required

Determine the probability of selecting You, Anna and Kevin

Assuming the selection process is fair;

Each employee has a probability of;

$Probability = \frac{1}{17}$

So:

$P(You\ n\ Anna\ n\ Kevin) = P(You) * P(Anna) * P(Kevin)$

$P(You\ n\ Anna\ n\ Kevin) = \frac{1}{17} * \frac{1}{17} * \frac{1}{17}$

$P(You\ n\ Anna\ n\ Kevin) = \frac{1}{4913}$

5 0

4 years ago