Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
14^3/100 i think im not 100% sure so if its wrong dont get mad
Step-by-step explanation:
-46
Hope this helps!
May I please have brainliest? :D
The first box is -7 and the other one is just 7
The first equation can be simplified down to 3 and -\frac{3}{2}[/tex]. Therefore, ">" is correct.
The second equation can be simplified down to 12 and 6.25. Therefore, "<" is incorrect. It should be ">".
