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fiasKO [112]
2 years ago
7

The sum of two integers with different signs is eight give to possible integers that fit this description

Mathematics
1 answer:
Soloha48 [4]2 years ago
8 0
An easy way is to do this
the 2 numbers are -x and x+8 where x is an integer

we can generate lots of numbers this way

example
-1 and 9
-2 and 10
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Jackie cut a 2 yard spool into 5 equal lengths of ribbon what is the length of each ribbon in yards
ratelena [41]
2/5 yards 
i hope its right
5 0
3 years ago
Read 2 more answers
Please help me with those question please help with out number 1
alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

------------------------------------------------------------------------------------------

2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

-------------------------------------------------------------------------------------------

3)

x = 0, y = 1

x = 1, y = \frac{7}{5}

x = 5, y = 3

x = 10, y = 5

-------------------------------------------------------------------------------------------------

4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

y=5x+5

When x = 0, y = ?

y=5(0)+5\\y=0+5\\y=5

When x = 1, y = ?

y=5(1)+5\\y=5+5\\y=10

When x = 2, y = ?

y=5(2)+5\\y=10+5\\y=15

When x = 3, y = ?

y=5(3)+5\\y=15+5\\y=20

-------------------------------------------------------------------------------------------------------

2)

y=5x-2

When x = 0, y = ?

y=5(0)-2\\y=0-2\\y=-2

When x = 2, y = ?

y=5(2)-2\\y=10-2\\y=8

When x = 4, y = ?

y=5(4)-2\\y=20-2\\y=18

When x = 6, y = ?

y=5(6)-2\\y=30-2\\y=28

----------------------------------------------------------------------------------------------------

3)

y=\frac{2}{5}x +1

When x = 0, y = ?

y=\frac{2}{5}(0) +1

y=0 +1\\y=1

When x = 1, y = ?

y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1

y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5}  \\y=\frac{7}{5}

When x = 5, y = ?

y=\frac{2}{5}(5) +1\\y=2+1\\y=3

When x = 10, y = ?

y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5

-------------------------------------------------------------------------------------------------

4)

y=15x+2

When x = 0, y = ?

y=15(0)+2\\y=0+2\\y=2

When x = 1, y = ?

y=15(1)+2\\y=15+2\\y=17

When x = 2, y = ?

y=15(2)+2\\y=30+2\\y=32

When x = 5, y = ?

y=15(5)+2\\y=75+2\\y=77

4 0
3 years ago
Read 2 more answers
Which two ratios form a proportion? A) 1 : 3 and 6 : 3 B) 1 : 3 and 3 : 6 C) 3 : 1 and 9 : 3 D) 3 : 1 and 3 : 9
tamaranim1 [39]

Answer:

c

Step-by-step explanation:

you have to set them up as a fraction and see if they are an equivalent fraction and if they are thats the proportion

4 0
3 years ago
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The goalie on the Iceblades hockey team saves (blocks) 73% of the opponent's shots. With 10 minutes to go, the Iceblades are ahe
guapka [62]

1. The paired digits 00 to 99 represent 100 shots.

blocked

Let 00 to 72 = a shot that is saved. Which digits represent a goal scored? Explain.

Write your answer in the space below.

The answer is 73 to 99

2. Each group represents the 5 shots taken by the other team. To win the game, the Ice blades cannot let the other team score any goals.

For a group to be a success, how many of the 5 shots does the goalie need to save?

Write your answer in the space below.

The answer to the question Is all 5.

3. Group 1 is a success. Explain why.

Write your answer in the space below.

Group 1 is a success because none of the numbers 73 and 99 show up.

4. In this simulation, which groups are successes? How many successes are there in the 10 groups?

Write your answer in the space below.

1,3,10

There are 3.

5. Estimate the probability the Ice blades will win the game. Give your answer as a percent.

Write your answer in the space below.

3/10=30%

4 0
3 years ago
Find the values of x and y that makes each equation true. –(5y)i+12=4x+25i
vovikov84 [41]

Equate real part and imaginary part:

LHS:

real part -- 12

imaginary part -- 5y

RHS:

real part = 4x

imaginary part = 25

Equating::

12 = 4x

x = 12/4

x = 3

Again:

5y = 25

y = 25/5

y = 5

So,

x = 3

y = 5

5 0
1 year ago
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