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3 years ago

Round $99.20 to the nearest ten

2 answers:

4 0

Take the first 9 is in yours tens place so you want to take the second 9 and round up because anything 5 or more goes up and 4 or less stays the same

Anestetic [448]3 years ago

4 0

$100 I thinks this the answer

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40 points David invests $10,000 in a savings account that pays 3.5% simple interest. If David makes no withdrawals or deposits t

sweet [91]

Answer:

FV= $12,450

Step-by-step explanation:

Giving the following information:

David invests $10,000 in a savings account that pays 3.5% simple interest.

<u>To calculate the future value, we need to use the following formula.</u>

FV= PV*(1+i*n)

n= 7

i= 0.035

PV= 10,000

FV= 10,000*(1+0.035*7)

FV= $12,450

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3 years ago

Yum-Yum-Yum restaurant has just increased the wages they pay their employees. to help offset this added expense, Yum-Yum-Yum mus

nignag [31]

Answer:

12% of 7.99

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3 years ago

The curved part of this figures is a semicircle.

SCORPION-xisa [38]

The answer is 14+8.125π units².<span>
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3 years ago

Read 2 more answers

The cost for each soda is $2.25. If your friend Calvin buys a certain number of Coca-Colas (c) and Mountain Dews (m), which answ

levacccp [35]

Answer:

2.25(c+m)

Step-by-step explanation:

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3 years ago

The United States Coast Guard assumes the mean weight of passengers in commercial boats is 185 pounds. The previous value was lo

Valentin [98]

Answer:

There is a 5.5% probability that a random sample of passengers will have a mean weight that is as extreme or more extreme (either above or below the mean) than was observed in this sample.

Step-by-step explanation:

To solve this problem, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

In this problem, we have that:

$\mu = 185, \sigma = 26.7, n = 48, s = \frac{26.7}{\sqrt{48}} = 3.85$

The weights of a random sample of 48 commercial boat passengers were recorded. The sample mean was determined to be 177.6 pounds. Find the probability that a random sample of passengers will have a mean weight that is as extreme or more extreme (either above or below the mean) than was observed in this sample.

The probability of an extreme value below the mean.

This is the pvalue of Z when X = 177.6.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{177.6 - 185}{3.85}$

$Z = -1.92$

$Z = -1.92$ has a pvalue of 0.0274.

So there is a 2.74% of having a sample mean as extreme than that and lower than the mean.

The probability of an extrema value above the mean.

Measures above the mean have a positive z score.

So this probability is 1 subtracted by the pvalue of $Z = 1.92$

$Z = 1.92$ has a pvalue of 0.9726.

So there is a 1-0.9726 = 0.0274 = 2.74% of having a sample mean as extreme than that and above than the mean.

Total:

2*0.0274 = 0.0548 = 0.055

There is a 5.5% probability that a random sample of passengers will have a mean weight that is as extreme or more extreme (either above or below the mean) than was observed in this sample.

4 0

3 years ago