Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
Step-by-step explanation:
We have two conditions:
Bella: y = 25x + 60 = 25(10) + 60 = 250 + 60 = 310
Heather: y = 30x + 10 = 30(10) + 10 = 300 + 10 = 310
Answer: 24m+28
Step-by-step explanation:
you would distribute the -4 threw eveything
so it would be 24m+28
Answer:
3 minutes would be 0.05 hours.
Step-by-step explanation:
Simply divide the minute value by 60 and you get 0.05.
