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inn [45]
3 years ago
12

If a 67 degree angle is complementary to angle Q, what is the measure of angle Q?

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
8 0

Answer:

23°

Step-by-step explanation:

Complementary angles add up to 90°

67 + X = 90

X = 90 - 67

X = 23°

Vikentia [17]3 years ago
4 0

Answer:

Q = 23

Step-by-step explanation:

Complementary angles add to 90 degrees

67+Q =90

Subtract 67 from each side

67+Q -67 = 90-67

Q = 23

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1) Madison went shopping and spent $125 she paid $45 in Texas what was the sale tax rate (percent)
Gnesinka [82]

Answer:

170

Step-by-step explanation:

<em>How the sales tax de-calculator works </em>

<em>Step 1: take the total price and divide it by one plus the tax rate. </em>

<em>Step 2: multiply the result from step one by the tax rate to get the dollars of tax. </em>

<em>Step 3: subtract the dollars of tax from step 2 from the total price. </em>

<em>Pre-Tax Price = TP – [(TP / (1 + r) x r] </em>

<em>TP = Total Price.</em>

3 0
3 years ago
I need the answers please help 60points
enyata [817]
In 22, you're looking for the vertical height of the triangle. You're given the angle opposite the side you want to find (which I'll call x) and the length of the hypotenuse. This sets you up with the relation

\sin2^\circ=\dfrac x{1600}\implies x\approx55.84\text{ m}

In 23, you're given a similar situation, except now you're looking for the angle (I'll call it \theta) in the triangle opposite the side denoting the height of the airplane. So this time,

\sin\theta=\dfrac{1500}{5000}=\dfrac3{10}\implies\theta=\arcsin\dfrac3{10}\approx17.46^\circ
6 0
3 years ago
Read 2 more answers
Help asap pls! thanks :)
eduard

The correct answer would be A -2b ^^

HTH ^^

Brainliest would be great is possible! ^^

3 0
3 years ago
Here is another problem that can also be solved by working backwards.
g100num [7]
According to my brain, Maddy picked 6 cucumbers.
5 0
3 years ago
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Which is the approximate solution for the system of equations 3x+4y=2 and 4x+y=-4
harina [27]

3x+4y=2\qquad\text{subtract 3x from both sides}\\\\4y=-3x+2\qquad\text{divide both sides by 4}\\\\y=-\dfrac{3}{4}x+\dfrac{2}{4}\to y=-\dfrac{3}{4}x+\dfrac{1}{2}\\\\for\ x=0\to y=-\dfrac{3}{4}(0)+\dfrac{1}{2}=0+\dfrac{1}{2}=\dfrac{1}{2}\to\left(0,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=-\dfrac{3}{4}(2)+\dfrac{1}{2}=-\dfrac{3}{2}+\dfrac{1}{2}=-\dfrac{2}{2}=-1\to(2,\ -1)\\--------------------------------\\

4x+y=-4\qquad\text{subtract 4x from both sides}\\\\y=-4x-4\\\\for\ x=0\to y=-4(0)-4=0-4=-4\to(0,\ -4)\\\\for\ x=-1\to y=-4(-1)-4=4-4=0\to(-1,\ 0)\\\\Answer:\ \boxed{A.\ (-1.4,\ 1.5)}

6 0
3 years ago
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