Cp=7512.75×[100÷(100+77÷4)]
=7512.75×(100÷119.25)
=6300
c.p=6300
The value of x is 1/13 (4th choice)
Step-by-step explanation:
![{a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} }](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%20%3D%20%20%5Csqrt%5Bn%5D%7B%20%7Ba%7D%5E%7Bm%7D%20%7D%20)
If 14^x = ¹³√14, what value of <em>x </em>makes this equation true?
![\sqrt[13]{14} = {14}^{x} \\ \sqrt[13]{14} = {14}^{ \frac{1}{13} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B13%5D%7B14%7D%20%20%3D%20%20%7B14%7D%5E%7Bx%7D%20%20%5C%5C%20%20%5Csqrt%5B13%5D%7B14%7D%20%20%3D%20%20%7B14%7D%5E%7B%20%5Cfrac%7B1%7D%7B13%7D%20%7D%20)
So, the value of <em>x</em> is 1/13 (4th choice)
<em>Hope</em><em> </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>
B. All rectangles are parallelograms. <span />
Answer:
Step-by-step explanation:
The segment joining an original point with its rotated image forms a chord of the circle of rotation containing those two points. The center of the circle is the center of rotation.
This means you can find the center of rotation by considering the perpendicular bisectors of the segments joining points with their images. Here, the only proposed center that is anywhere near the perpendicular bisector of DE is point M.
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Segment AD is perpendicular to corresponding segment FE, so the angle of rotation is 90°. (We don't know which way (CW or CCW) unless we make an assumption about which is the original figure.)
Answer:
36.25 and 307.18
Step-by-step explanation:
both are 100 times greater than 20.342.
