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Naddika [18.5K]
3 years ago
12

01:54:24

Chemistry
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

[C]

Explanation:   -Cause i took the test on engenuity

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The first one is color change
Second is the precipitate present
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3 years ago
Which of the following would force the reaction to favor the produc to favor the products ? CaCO3(8) 2H3O'(aq) Cal(aq) + 3H200)
kotykmax [81]

Explanation:

(a)   According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the eqilibrium in a direction that will oppose the change.

For example, CaCO_{3}(s) + 2H_{3}O^{+}(aq) \rightleftharpoons Ca^{2+}(aq) + 3H_{2}O(l) + CO_{2}(g)

So, in this reaction when we any of the reactants then it means there is less stress on reactant side. Hence, the reaction will move in the backward direction.

Whereas when we remove CO_{2} then there will be decrease in concentration of products as the concentration of carbon dioxide has decreased. Hence, the reaction will shift on the product side, that is, reaction will shift in the forward direction.

Thus, we can conclude that out of the given options removing CO_{2} as it is formed would force the reaction to favor the produc to favor the products.

(b)   As the reaction equation is as follows.

            3NO(g) \rightleftharpoons N_{2}O(g) + NO_{2}(g) + Heat

Since, it is an exothermic reaction, that means when temperature is increasing then more amount of energy will release on the product side.

Hence, the reaction will shift on the reactant side, that is on the left hand side equilibrium will shift.

5 0
4 years ago
If the neutral atom of an element has only 4 valence electrons it must be in which group? 1. IVB 2. VA 3. VIIA 4. VIA 5. IVA 6.
lisabon 2012 [21]

Answer:option

Option 5..IVA

Explanation:

5 0
4 years ago
PLEASE HELP ASAP <br> Half equation for zinc atoms changing into zinc ions
Yuri [45]

Answer:

Zn(s) -> Zn2+(aq) + 2e

Explanation:

Zinc atoms = no charge

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The process of half equation for zinc is called oxidation .

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3 0
4 years ago
if you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of
OverLord2011 [107]

Answer:

The mole fraction of codeine is 5.4%

Explanation:

Mole fraction = Mole of solute / Total moles (Mole solute + Mole solvent)

Solute (Codeine)

Molar mass 299.36 g/m

Mass / Molar mass = Mole →  46.85 g /299.36 g/m = 0.156 moles

Solvent (Ethanol)

Molar mass 46.07 g/m

125.5 g / 46.07 g/m = 2.724 moles

Mole fraction (Codeine) 0.156 / (0.156 + 2.724) → 0.054

3 0
3 years ago
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