In the reaction Sn(s) + 2H+(aq) → Sn2+ (aq) + H2(g)
from this reaction, we get that Sn loses from 0 to 2 electrons so it's oxidized So it is the reducing agent.
and H gains from 0 to 1 electrons so, it's reduced so ∴ it is the oxidizing agent
Answer:
The answer to your question is:
Explanation:
Data
moles H=?
moles of N = 0.0969
moles of NH₃=?
N₂ (g) + 3 H₂ (g) ⇒ 2NH₃ (g)
Process
1.- Set a rule of three to calculate the moles of hydrogen
1 mol of nitrogen ------------- 3 moles of hydrogen
0.0969 moles of N ---------- x
x = (0.0969 x 3) / 1
x = 0.2907 moles of hydrogen
2.- Set a rule of three to calculate the moles of ammonia
1 mol of nitrogen -------------- 2 moles of ammonia
0.0969 mol of N -------------- x
x = (0.0969 x 2) / 1
x = 0.1938 moles of ammonia
multiply the number of each atom with its molecular mass. (see the periodic table)
5*12 + 12*1 = 72 gram per mole.
Or more accurately: 5*12.01078 + 12*1.007947 = 72.149264 g/mole
Subtract the number of protons from the mass number.
