I think you have to find a common multiple for the denominators 5 and 8 which would be 40. so it would be 6/40 and 2/40. then I think, you would add or multiple, depending on the situation, 6 and 2
Answer:
0 = -6
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−2(−2k+3)+4k=−2(6−3k)+2k
(−2)(−2k)+(−2)(3)+4k=(−2)(6)+(−2)(−3k)+2k(Distribute)
4k+−6+4k=−12+6k+2k
(4k+4k)+(−6)=(6k+2k)+(−12)(Combine Like Terms)
8k+−6=8k+−12
8k−6=8k−12
Step 2: Subtract 8k from both sides.
8k−6−8k=8k−12−8k
−6=−12
Step 3: Add 6 to both sides.
−6+6=−12+6
0=−6
Answer:
13
Step-by-step explanation:
Given the equation h(x) = 2x²
To solve for h(-2) + 5 then, we need to break the problem into two parts
First, we will solve for the function h(x) at x = -2
h(x) = 2x² so
h(-2) = 2(-2)²
h(-2) = 8
Knowing this, we can plug 8 into our original expression for h(-2)
8 + 5
This gives us 13
Answer:
6600
Step-by-step explanation:
y = 15000( 1.2) ^ (x/3)
Let x = 6 years
y = 15000( 1.2) ^ (6/3)
y = 15000( 1.2) ^ (2)
y = 15000( 1.44)
y =21600
This is the total amount in the account
We want the profit
Subtract the original amount in the account
21600-15000
6600
Answer:
"impossible"
Step-by-step explanation:
I think. :/