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schepotkina [342]
3 years ago
7

17. If the perimeter of square 1 is 104 ft and the

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

none of the choices is correct

Step-by-step explanation:

To find the length of the side of square 1, divide the perimeter, 104÷4 = 27

That is the hypotenuse of the triangle.

The square of 27 is 729

Subtract the given square of Square 2, 576

729 - 576 = 153

Take the square root of 153 to find the length of the side of Square 3

√153= 12.37

I hope this helps. It's just a bit more challenging version of Pythagorean Theorem: a² + b² = c²

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riadik2000 [5.3K]
I have worked out the answer to the question, I hope it helps you. Please do not forget to check if this answer if reliable, I am not always correct

8 0
2 years ago
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Find the slope of the line that passes through the ordered pairs (-2,8) and (-9,19)
Ilia_Sergeevich [38]

Answer:

slope: -11/7

Step-by-step explanation:

Slope is equal to the change in yy over the change in xx, or rise over run.

m=change in ychange in xm=change in ychange in x

The change in xx is equal to the difference in x-coordinates (also called run), and the change in yy is equal to the difference in y-coordinates (also called rise).

m=y2−y1x2−x1m=y2-y1x2-x1

Substitute in the values of xx and yy into the equation to find the slope.

m=19−(8)−9−(−2)m=19-(8)-9-(-2)

Simplify.

m=−11/7

6 0
3 years ago
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Jaylen will deposit $1,750 in an account that earns 6% simple interest every year. His best friend, Eli, will deposit $1,600 in
Novay_Z [31]

Answer:

Jaylen- 2275

Eli- 2405.85

Jaylen

1750 x 0.06 x 5 =525

525 + 1750 = 2275

He makes 525 simple interest in those 5 years so you add that to the initial amount, to find his total after 5 years.

Eli

A= 1600(1+0.085)^5

1600(1.085)^5

2405.85

Hope this helps ^-^

6 0
3 years ago
5 friends are sharing 8 pieces of pizza equally.How many pieces will each friend get to eat?
Korolek [52]

Answer:

8÷5 = 1 . 6

Step-by-step explanation:

They will divide the pizzas into 5 pieces further

5 0
3 years ago
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An=an-1+6an-2 <br> n&gt;2 a0=3 a1=6
Svetach [21]
\begin{cases}a_0=3\\a_1=6\\a_n=a_{n-1}+6a_{n-2}&\text{for }n>2\end{cases}

Let the generating function for a_n be

A(x)=\displaystyle\sum_{n\ge0}a_nx^n

Multiplying both sides by x^{n-2}

a_nx^{n-2}=a_{n-1}x^{n-2}+6a_{n-2}x^{n-2}

Summing both sides over the non-negative integers greater than or equal to 2 gives

\displaystyle\sum_{n\ge2}a_nx^{n-2}=\sum_{n\ge2}a_{n-1}x^{n-2}+6\sum_{n\ge2}a_{n-2}x^{n-2}
\displaystyle\frac1{x^2}\sum_{n\ge2}a_nx^n=\frac1x\sum_{n\ge1}a_nx^n+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(\sum_{n\ge0}a_nx^n-a_0-a_1x\right)=\frac1x\left(\sum_{n\ge0}a_nx^n-a_0\right)+6\sum_{n\ge0}a_nx^n
\displaystyle\frac1{x^2}\left(A(x)-3-6x\right)=\frac1x\left(A(x)-3\right)+6A(x)
A(x)=\dfrac{3x+3}{1-x-6x^2}
A(x)=\dfrac3{5(1+2x)}+\dfrac{12}{5(1-3x)}

For |x|, the two series converge to

\displaystyle A(x)=\frac35\sum_{n\ge0}(-2x)^n+\frac{12}5\sum_{n\ge0}(3x)^n
\implies A(x)=\displaystyle\sum_{n\ge0}\dfrac{3(-2)^n+12(3)^n}5x^n
a_n=\dfrac{3(-2)^n+12(3)^n}5=\dfrac{3(-2)^n+4(3)^{n+1}}5
5 0
3 years ago
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