Answer:
<h3>The ratio of technicians to all helpers is 11 : 7, or
or 11 to 7.</h3>
Step-by-step explanation:
- Given that there are 7 ushers and 11 technicians helping at the Harper Middle School fall play.
- Let x be the number of ushers ( or helpers ).
- Therefore x=7 helpers.
- Let y be the number of technicians.
- Therefore y=11 technicians.
<h3>To find the ratio of technicians to all helpers :</h3>
That is to find the ratio of y to x.
We can write the ratio of technicians to all ushers(helpers) as y : x
Which implies that 11 : 7, (since y=11 and x=7)
Or or 11 to 7
<h3>The ratio of technicians to all helpers is 11 : 7, or
or 11 to 7</h3>
You left it out, but I'm thinking that there must be an 'x' next to the '20.50' in the function. I'm so sure of it that I'll assume it, as I proceed to answer the question:
C(x) = 20.50x + 2,000
Subtract 2,000 from each side: C - 2,000 = 20.50 x
Divide each side by 20.50 : x = (C - 2,000) / 20.50
When C = $625,000 . . .
x = (625,000 - 2,000) / 20.50 = 623,000 / 20.50 = 30,390.2439
<em>30,390 complete units</em> are produced, and there are 5 bucks left over,
to split up among all the loyal employees who worked with such diligence and dedication to make it happen. The company's senior management will graciously add each worker's share to his gross pay before taxes for the second month following the close of the current quarter, with a photocopied note inserted in the pay envelope, expressing management's sincere thanks to everyone, an admonition not to spend it all in one place, and a reminder that no matter how many festivals to their god they need to go out to the desert to celebrate, their tally of bricks for the next quarter shall not be diminished.
Answer:
C. (-4,2)
Step-by-step explanation:
Answer:
- SSS
- the answer is A
- SAS
- 1, 2, 3, 4, and 5
- using alternate interior angles theorem on angles A and C, verticle angles theorem on angle O, and the Parallelogram Diagonals Theorem Converse you can prove triangles ADO and BOC are similar. Then using CPCTC "Corresponding parts of congruent triangles are congruent" you can prove that line segment AO is congruent (equal) to line segment CO
Step-by-step explanation:
if my answer helps plz give me brainliest :)
let's bear in mind that
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
so, let's do away with the denominators by multiplying both sides by the LCD of all fractions, in this case 6.
