Answer:
Rise over Run.
Step-by-step explanation:
If it's on a line on a graph you count how many it goes up until it's aligned with the next point and then you count how ever many over until it hits it. So it could be 2 up and 4 over making the slope 2/4.
I'm sorry that might not make much sense I'm bad at explaining but let me know if that helps at all!!
Answer:
![Meeting\ Time = 6:03\ pm](https://tex.z-dn.net/?f=Meeting%5C%20Time%20%3D%206%3A03%5C%20pm)
Step-by-step explanation:
Given
![Start\ Time= 5:45pm](https://tex.z-dn.net/?f=Start%5C%20Time%3D%205%3A45pm)
![Lixin = 18\ min/round](https://tex.z-dn.net/?f=Lixin%20%3D%2018%5C%20min%2Fround)
![Khairul = 360\ seconds/round](https://tex.z-dn.net/?f=Khairul%20%3D%20360%5C%20seconds%2Fround)
![Devi = 4minutes/2\ rounds](https://tex.z-dn.net/?f=Devi%20%3D%204minutes%2F2%5C%20rounds)
Required
Determine their next meeting time
First, we need to get their unit rate in minutes per round
![Lixin = 18\ min/round](https://tex.z-dn.net/?f=Lixin%20%3D%2018%5C%20min%2Fround)
![Khairul = 360\ seconds/round](https://tex.z-dn.net/?f=Khairul%20%3D%20360%5C%20seconds%2Fround)
Convert 360 seconds to minutes
![Khairul = \frac{360}{60} min/round](https://tex.z-dn.net/?f=Khairul%20%3D%20%5Cfrac%7B360%7D%7B60%7D%20min%2Fround)
![Khairul = 6 min/round](https://tex.z-dn.net/?f=Khairul%20%3D%206%20min%2Fround)
![Devi = 4minutes/2\ rounds](https://tex.z-dn.net/?f=Devi%20%3D%204minutes%2F2%5C%20rounds)
Divide by 2/2
![Devi = 2mins/round](https://tex.z-dn.net/?f=Devi%20%3D%202mins%2Fround)
So, we have:
![Lixin = 18\ min/round](https://tex.z-dn.net/?f=Lixin%20%3D%2018%5C%20min%2Fround)
![Khairul = 6 min/round](https://tex.z-dn.net/?f=Khairul%20%3D%206%20min%2Fround)
![Devi = 2mins/round](https://tex.z-dn.net/?f=Devi%20%3D%202mins%2Fround)
Next, is to determine the LCM of 18, 6 and 2
![18=2 * 3 * 3](https://tex.z-dn.net/?f=18%3D2%20%2A%203%20%2A%203)
![6 = 2 * 3](https://tex.z-dn.net/?f=6%20%3D%202%20%2A%203)
![3 = 3](https://tex.z-dn.net/?f=3%20%3D%203)
Their LCM is:
![LCM = 2 * 3 * 3](https://tex.z-dn.net/?f=LCM%20%3D%202%20%2A%203%20%2A%203)
![LCM = 18](https://tex.z-dn.net/?f=LCM%20%3D%2018)
This means that they will meet 18 minutes after their initial time of departure.
So:
![Meeting\ Time = 5:45\ pm + 18\ minutes](https://tex.z-dn.net/?f=Meeting%5C%20Time%20%3D%205%3A45%5C%20pm%20%2B%2018%5C%20minutes)
![Meeting\ Time = 6:03\ pm](https://tex.z-dn.net/?f=Meeting%5C%20Time%20%3D%206%3A03%5C%20pm)
Answer:13( n + 5) = 91
Step-by-step explanation: solve the parenthesis first and then multiply that by 13
Answer:
f(4) = 6
Step-by-step explanation:
f(x) = 3x - 6
f(4) = 3(4) - 6
f(4) = 12 - 6
f(4) = 6
Step-by-step explanation:
![\cos \theta = \frac{1}{ \sec\theta } = - \frac{3}{ \sqrt{30} } = - \frac{3 \sqrt{30} }{30} = - \frac{ \sqrt{30} }{10}](https://tex.z-dn.net/?f=%20%5Ccos%20%5Ctheta%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%5Csec%5Ctheta%20%7D%20%20%3D%20%20-%20%20%5Cfrac%7B3%7D%7B%20%5Csqrt%7B30%7D%20%7D%20%20%3D%20%20-%20%20%5Cfrac%7B3%20%5Csqrt%7B30%7D%20%7D%7B30%7D%20%20%20%3D%20%20-%20%20%5Cfrac%7B%20%5Csqrt%7B30%7D%20%7D%7B10%7D%20)
![\cos( \frac{\pi}{2} - \theta )= \cos \frac{\pi}{2} \cos \theta + \sin \frac{\pi}{2} \sin \theta](https://tex.z-dn.net/?f=%20%5Ccos%28%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20-%20%20%5Ctheta%20%29%3D%20%20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%20%5Ccos%20%5Ctheta%20%20%2B%20%20%20%5Csin%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%20%5Csin%20%5Ctheta%20)
Note that
![\sin( - \theta) = - \sin \theta](https://tex.z-dn.net/?f=%20%5Csin%28%20-%20%5Ctheta%29%20%3D%20%20-%20%20%5Csin%20%5Ctheta)
![\cos \frac{\pi}{2} = 0 \: \: \: \: \: \sin \frac{\pi}{2} = 1](https://tex.z-dn.net/?f=%20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%20%3D%200%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Csin%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%20%3D%201)
Therefore,
![\cos( \frac{\pi}{2} - \theta ) = 0.97](https://tex.z-dn.net/?f=%20%5Ccos%28%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20-%20%20%5Ctheta%20%29%20%20%3D%200.97)