Question

I NEED HELP PLEASE, THANKS! :)

Answer 1

Answer:

124

Step-by-step explanation:

First subtract 6 to both sides.

$\sqrt[5]{249-2x} = 1$

Then take the 5th power of both sides to remove the radical.

$249-2x=1^5$

Which is essentially:

-2x = 1 - 249

-2x = -248

Divide both sides by -2

x = 124

And there ya go :)

Answer 2

Answer:

x = 124

Step-by-step explanation:

$6 + \sqrt[5]{249 - 2x} = 7 \\ \sqrt[5]{249 - 2x} = 7 - 6 \\ \sqrt[5]{249 - 2x} = 1 \\ {\sqrt[5]{249 - 2x} }^{5} = {1}^{5}$

$249 - 2x = 1 \\ - 2x = 1 - 249 \\ - 2x = - 248 \\ \frac{ - 2x}{ - 2} = \frac{ - 248}{ - 2}$

$x = 124$