3 years ago

For the function N(y) = 4|3y – 8– 4, evaluate N(y) + N(1).

Mathematics

1 answer:

Reil [10]3 years ago

7 0

Answer:

4|3y-8|+12

Step-by-step explanation:

N(1)=4|3(1)-8|-4

N(1)=16

Now we have:

N(y)+N(1)=4|3y-8|-4+16

N(y)+N(1)=4|3y-8|+12

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