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Ede4ka [16]
3 years ago
8

Which graph represents a proportional relationship? NextReset

Mathematics
1 answer:
gavmur [86]3 years ago
6 0
The answer to that question is <span>Practice telling whether or not the </span>relationship<span> between two quantities is </span>proportional<span> by looking at a</span>graph<span> of the </span>relationship<span>.</span>
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John has 6 pairs of pants and 3 shirts. How many possible outfits consisting of one shirt and
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Answer:

18

Step-by-step explanation:

3 shirts for each pants

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How many permutations exist of the letters PQRS and T taking four at a time
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Looking at the permutation formula, we have n!/(n-r)!. n is the number of objects to select from and r is how many are to be picked at once. And 1 means multiply from there down basically. 5!/(5-4)!= 5*4*3*2*1/1. 5 times 4 is 20 times 3 is 60 times 2 is 120 times 1 is 1 so 120/1 is 120. There are 120 total combinations to be made from P, Q, R, S and T. 

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A football team gained 9 yards on one play and then lost 22 yards on the next and
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Find sin4a and cos4α, if tanα=3
Mashcka [7]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

Sin2α = 2SinαCosα.

Cos2α = (Cosα)^2 - (Sinα)^2.

Sin4α can be written as Sin2(2α).

Similarly Cos4α can be written as Cos2(2α).

Sin 4\alpha = 2Sin 2\alpha \times Cos 2\alpha = 2Sin 2\alpha \times(Cos^{2} \alpha - Sin^{2} \alpha ) = 4Sin \alpha \times Cos \alpha \times (Cos^{2} \alpha - Sin^{2} \alpha )

It is given that  tanα=3.

Sinα(Sinα) =  \frac{9}{10} [Sec^{2} \alpha = 1 + 3^{2} = 10.\\Cos^{2} \alpha = \frac{1}{10} \\Sin^{2} \alpha = 1 - \frac{1}{10} = \frac{9}{10}], the values either be both positive or both negative, as the value of tanα is positive only on first and third quadrant.

Sin4α = 4\times \sqrt{(\frac{9}{10} )} \times  \sqrt{(\frac{1}{10} )} \times (\frac{1 - 9}{10} ) = -\frac{4\times8\times3}{100} = -\frac{96}{100}.

Cos4α = Cos^{2} 2\alpha  - Sin^{2} 2\alpha = (Cos^{2} \alpha - Sin^{2} \alpha )^{2} - Sin^2 {2\alpha } = (Cos^{2} \alpha - Sin^{2} \alpha )^{2} - (2Sin \alpha Cos \alpha )^{2} = (-\frac{8}{10} )^{2} - \frac{4\times9}{100} = \frac{64 - 36}{100} = \frac{28}{100} = \frac{7}{25}

7 0
3 years ago
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