To do these, start by looking at the "b" value -6.
divide it by 2
-6/2 = -3
now square this number
(-3)^2 = 9
this is what you need for the "c" value
there is only a 5 for the c value so add 4 to both sides of the equation. ( +4 = +4)
y +4 = x^2 -6x +5 +4
y +4 = x^2 -6x +9
y +4 = (x -3)^2
y = (x -3)^2 - 4
vertex ( 3, -4) upwards facing like a bowl, because the "a" value is positive. So the vertex is the minimum, lowest point on the graph.
<span>Box plots give the five number summary of the data set. The whiskers indicate the minimum daily travel time, which is 11 minutes, and the maximum daily travel time, which is 45 minutes. These values are not outliers because they are connected to the box with whiskers. Meanwhile, the box indicates that the first quartile of the data set is 16, the median is 28, and the third quartile is 36.</span>
I found h max = 64 feet
Explanation: Ok...probably you can do this differently but I would try to find the vertex of the parabola describing the trajectory: 1) derive it: h ` ( t ) = 64 − 32 t 2) set derivative equal to zero: 64 − 32 t = 0 t = 64 32 = 2 sec 3) use this value of t into your trajectory: h ( 2 ) = h max 64 ⋅ 2 − 16 ⋅ 4 = 64 feet .
Answer
-6y+4
4Step-by-step explanation:
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-2x-4y+{\color{#c92786}{10}}+2x-2y{\color{#c92786}{-6}}
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