210/20=10.5 per hour
So
2000/10.5=190 hours
Complete Question:
Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ? For what values?(Make sure to use an inequality)
Answer:
y < 3
Step-by-step explanation:
The given two fractions are:
and 
We have to tell for which range of values is the value of first fraction larger than the second fraction. This can be done by setting up an inequality as shown:

The range of y which will satisfy this inequality will result in first fraction of larger value as compared to the second fraction.
Multiplying both sides of inequality by 12, we get:

This means, for y lesser than 3, the value of first fraction is larger than the second one.
Answer: I got x= -2y
1- x-2y=1
Cancel 1 on both sides.
−x−2y=0
Add 2y to both sides.
−x=2y
Multiply both sides by -1.
x=−2y
there if that helps :)
Answer:
Step-by-step explanation: bjffngjkldsldgns
Answer:
<h2>10.3seconds</h2>
Step-by-step explanation:
Step one:
given data
acceleration,a= 10ft/sec^2
final velocity v= 70mph
first, let is convert mph to ft/sec
1mph is 1.46667 ft/sec
70 mph is x
cross multiply we have
x= 102.7ft/s
Step two:
we are using the first equation of motion
v=u+at
initial velocity u= 0m/s
102.7=0+10*t
102.7=10t
divide both sides by 10
t=10.3seconds