Answer:
84.3%
Step-by-step explanation:
You first find the frequency. You do this by multiplying the frequency density by the class length.
<span>(a) At the end of Month 0, about how many more insects were in Pod A than Pod B? Explain.
In Pod A, the point is higher than 50, it could be 60 to 70 insects. Pod B has 20 insects. So, Pod A has at least 40 insects more than Pod B.
(b) Find and compare the growth rates of each pod. Show your work.
Pod A: (0,60) ; (1,80) ; (2,100)
(80-60)/60 = 0.33
(100-80)/80 = 0.25
Pod B: (0,20) ; (1,44) ; (2,97)
(44-20)/20 = 1.2
(97-44)/44 = 1.2
Based on my computation, the rate of Pod A is lower than the rate of Pod B.
(c) When does the population in Pod B exceed the population in Pod A? Explain.
Pob B exceeds the population of Pod A at the END OF MONTH 4.
Pod A has a population of less than 200 while Pod B has a population of 469.</span>
R(–3, 1), S(4, 5)
calculate vector:
v=(4-(-3),5-1)=(7,4)
distance=length of vector=√(7²+4²)=√(49+16)=√(65)≈8.06226
rounded to the nearest tenth: 8.1
Answer:
-11.5>-9.5
Step-by-step explanation:
I think I took the test a long time ago
