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mestny [16]
2 years ago
13

Identify the zeros of f(x) = 2x^6 +2x^5

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
6 0

Answer:

0, -1

Step-by-step explanation:

zeros occur when 2x^6+2x^5=0

the first way for this to happen would be to set x to 0. both terms would become zero.

the second way is x = -1

first term becomes 2

second becomes -2

these add to zero

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Bumek [7]

Answer:

Step-by-step explanation:

\frac{b}{-3}+4< 13

Step 1: Subtract 4 form both sides

Step 2: Multiply both sides by (-3). when we are multiplying by (-3) the < will change to >.

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2 years ago
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3 years ago
21x =7?<br> A. x=3<br> B. None of these <br> C. x=147<br> D. x=28
Varvara68 [4.7K]

Answer: B

Step-by-step explanation:

To isolate x, you divide both sides by 21

21x=7

\frac{21x}{21}=\frac{7}{21}

x = 7/21

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Since, 1/3 is not an option, B is the correct answer

6 0
1 year ago
Simplify x to the 1/3 power (x to the 1/2 power + 2x to the 2 power )
OverLord2011 [107]

Answer:

x^(5/6) + 4(x^(7/3))


Step-by-step explanation:

Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )


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= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)

= x^(1/3+1/2) + 4(x^(1/3+2))

= x^(5/6) + 4(x^(7/3))


x^(1/3) is y such that y^3 = x

(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x


x^(1/2) = √2 = y such that y^2 = x

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vitfil [10]
The answer is 10. Hope this helps.
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